原題連結
題解
when you are asked to find the “k-th whatever-est something,” binary search is often adopted as the first step of the solution
以 \(d_k\) 為半徑的線段裡恰好有 \(k\) 個 \(a\)
code
#include<bits/stdc++.h>
#define ll long long
using namespace std;
int a[100005];
void solve()
{
int n,q;
cin>>n>>q;
for(int i=1;i<=n;i++) cin>>a[i];
sort(a+1,a+1+n);
while(q--)
{
int x,k;
cin>>x>>k;
int l=-1,r=2e8+10;
while(l+1<r)
{
int mid=(l+r)/2;
int p1=upper_bound(a+1,a+1+n,mid+x)-a-1;
int p2=lower_bound(a+1,a+1+n,x-mid)-a;
if(p1-p2+1<k) l=mid;
else r=mid;
}
cout<<r<<'\n';
}
}
int main()
{
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int t=1;
//cin>>t;
while(t--) solve();
return 0;
}