HDU 1240 Asteroids!

薛定谔的AC發表於2024-07-10

題目連結:HDU 1240 【Asteroids!】



思路


程式碼

#include <iostream>
#include <queue>
#include <stdlib.h>
#include <cstring>
#define ll long long
using namespace std;
const int N = 20;
const int M = 1e4;
struct point {
  int x, y, z, step;
}position[M],start, target;
int mp[N][N][N], n, dir[10][3] = {{1, 0, 0},  {-1, 0, 0}, {0, 1, 0},
                                  {0, -1, 0}, {0, 0, 1},  {0, 0, -1}};
bool vis[N][N][N];

bool check(int x, int y, int z) {
  return x >= 0 && x < n && y >= 0 && y < n && z >= 0 && z < n && vis[z][x][y] == 0 && mp[z][x][y] == 0;
}
void bfs() {
  queue<point> q;
  q.push(start);
  vis[start.x][start.y][start.z] = true;

  while (!q.empty()) {
    start = q.front();
    q.pop();
    if (start.x == target.x && start.y == target.y && start.z == target.z) {
      cout << n << " " << start.step << endl;
      return;
    }
    for (int i = 0; i < 6; i++) {
      point now = start;
      now.x += dir[i][0], now.y += dir[i][1], now.z += dir[i][2];
      if (check(now.x, now.y, now.z) == true) {
        vis[now.z][now.x][now.y] = true;
        now.step++;
        q.push(now);
      }
    }
  }
  cout << "NO ROUTE" << endl;
}

int main() {
  string s;
  while (cin >> s >> n) {
    memset(vis, 0, sizeof vis);

    for (int i = 0; i < n; i++) {
      for (int j = 0; j < n; j++) {
        for (int k = 0; k < n; k++) {
          char auxious;
          cin >> auxious;
          if (auxious == 'O') {
            mp[i][j][k] = 0;
          } else {
            mp[i][j][k] = 1;
          }
        }
      }
    }

    cin >> start.x >> start.y >> start.z;
    cin >> target.x >> target.y >> target.z;
    cin >> s;
    start.step = target.step = 0;

    bfs();
   }
  return 0;
}

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