電力系統分析(第二版)Hadi Saadat matlab 程式二(教材搬運)
例2.1
Vm=100;thetav=0;%電壓幅值和初始相角
Z=1.25;gama=60;%阻抗幅值和相角
thetai=thetav-gama;%電流相角
theta=(thetav-thetai)*pi/180;%化為弧度制
Im=Vm/Z;%電流幅值
wt=0:.05:2*pi;%wt from 0 to 2*pi
v=Vm*cos(wt);%瞬時電壓
i=Im*cos(wt + thetai*pi/180);%瞬時電流
p=v.*i;%瞬時功率
V=Vm/sqrt(2); I=Im/sqrt(2);%有效電壓和電流
P=V*I*cos(theta);%有功功率
Q=V*I*sin(theta);%無功功率
S=P+j*Q;%復功率
pr=P*(1+cos(2*(wt + thetav)));%式(2.6)
px=Q*sin(2*(wt + thetav));%式(2.8)
wt=180/pi*wt;%轉化為角度制
subplot(2,2,1), plot(wt, v, wt, i), grid
title(['v(t)=V_m cos\omegat, i(t)=I_m cos(\omegat +', num2str(thetai), ')'])
xlabel('\omegat,degree')
subplot(2,2,2), plot(wt, p), grid
title('p(t)=v(t) i(t)'), xlabel('\omegat, degree')
subplot(2,2,3), plot(wt, pr), grid
title('pr(t)Eq. 2.6'), xlabel('\omegat, degree')
subplot(2,2,4), plot(wt, px), grid
title('px(t)Eq. 2.8'), xlabel('\omegat, degree')
subplot(111)
例2.2
V = 1200; Z1= 60; Z2 = 6 + j*12; Z3 = 30 - j*30;
I1 = V/Z1; I2 = V/Z2; I3 = V/Z3;
S1= V*conj(I1), S2= V*conj(I2), S3= V*conj(I3) % conj 求共軛
S = S1 + S2 + S3
結果
S1 = 24000
S2 = 4.8000e+04 + 9.6000e+04i
S3 = 2.4000e+04 - 2.4000e+04i
S = 9.6000e+04 + 7.2000e+04i
例2.3
V = 200; Z1= 100; Z2 = 10 + j*20;
I1 = V/Z1; I2 = V/Z2;
S1= V*conj(I1), S2= V*conj(I2)
I = I1 + I2
S = S1 + S2, P = real(S); Q = imag(S);
PF = cos(angle(S))
thd = acos(0.8), Qd = P*tan(thd)
Sc = -j*(Q - Qd)
Zc = V^2/conj(Sc), C = 1/(2*pi*60*abs(Zc))
Sd = P + j*Qd;
Id=conj(Sd)/conj(V)
結果
S1 = 400
S2 = 8.0000e+02 + 1.6000e+03i
I = 6.0000 - 8.0000i
S = 1.2000e+03 + 1.6000e+03i
PF = 0.6000
thd = 0.6435
Qd = 900.0000
Sc = 0.0000e+00 - 7.0000e+02i
Zc = 0.0000 -57.1429i
C = 4.6420e-05
Id = 6.0000 - 4.5000i
例2.4
V = 1400;
S1= 35000 + j*120000; S2 = 10000 - j*40000; S3 = 15000;
S = S1 + S2 + S3, P = real(S); Q = imag(S);
PF = cos(angle(S))
I = conj(S)/conj(V)
thd = acos(0.8), Qd = P*tan(thd)
Sc = -j*(Q - Qd)
Zc = V^2/conj(Sc), C = 1/(2*pi*60*abs(Zc))
Sd = P + j*Qd;
Id=conj(Sd)/conj(V)
結果
S =6.0000e+04 + 8.0000e+04i
PF =0.6000
I = 42.8571 -57.1429i
thd = 0.6435
Qd = 4.5000e+04
Sc = 0.0000e+00 - 3.5000e+04i
Zc = 0.0000 -56.0000i
C = 4.7368e-05
Id = 42.8571 -32.1429i
例2.5
R = 1; X = 7; Z = R +j*X;
V1 = 120*(cos(-5*pi/180) + j*sin(-5*pi/180));
V2 = 100+j*0;
I12 = (V1 - V2)/Z;
I21 = -I12;
S12 = V1*conj(I12), S21 = V2*conj(I21)
SL = S12 + S21
PL = R*abs(I12)^2, QL = X*abs(I12)^2
結果
S12 =-9.7508e+01 + 3.6331e+02i
S21 = 1.0733e+02 - 2.9452e+02i
SL = 9.8265 +68.7858i
PL = 9.8265
QL = 68.7858
例2.6
E1=input('Source # 1 Voltage Mag. = ');
a1=input('Source # 1 Phase Angle = ');
E2=input('Source # 2 Voltage Mag. = ');
a2=input('Source # 2 Phase Angle = ');
R=input('Line Resistance = ');
X= input('Line Reactance = ');
Z= R + j*X; % 線路阻抗
a1 = (-30+a1:5:30+a1)'; % a1 變化+/- 30 度
a1r = a1*pi/180; % 角度轉弧度
k=length(a1);
a2=ones(k,1)*a2; % 建立列 a2
a2r = a2*pi/180; % 角度轉弧度
V1=E1.*cos(a1r) + j*E1.*sin(a1r);
V2=E2.*cos(a2r) + j*E2.*sin(a2r);
I12 = (V1 - V2)./Z; I21=-I12;
S1= V1.*conj(I12); P1 = real(S1); Q1 = imag(S1);
S2= V2.*conj(I21); P2 = real(S2); Q2 = imag(S2);
SL= S1+S2; PL = real(SL); QL = imag(SL);
Result1=[a1, P1, P2, PL];
disp(' ')
disp(' Delta 1 P-1 P-2 P-L ')
disp(Result1)
plot(a1, P1, a1, P2, a1, PL)
xlabel('Source #1 Voltage Phase Angle')
ylabel('P, Watts')
text(-26, -550, 'P1'), text(-26, 600,'P2'), text(-26, 100, 'PL')
結果
Source # 1 Voltage Mag. = 120
Source # 1 Phase Angle = -5
Source # 2 Voltage Mag. = 100
Source # 2 Phase Angle = 0
Line Resistance = 1
Line Reactance = 7
Delta 1 P-1 P-2 P-L
-35.0000 -872.2049 967.0119 94.8070
-30.0000 -759.8461 832.1539 72.3078
-25.0000 -639.5125 692.4848 52.9723
-20.0000 -512.1201 549.0676 36.9475
-15.0000 -378.6382 402.9938 24.3556
-10.0000 -240.0828 255.3751 15.2923
-5.0000 -97.5084 107.3349 9.8265
0 48.0000 -40.0000 8.0000
5.0000 195.3349 -185.5084 9.8265
10.0000 343.3751 -328.0828 15.2923
15.0000 490.9938 -466.6382 24.3556
20.0000 637.0676 -600.1201 36.9475
25.0000 780.4848 -727.5125 52.9723
例2.7
V1 = 207.85/sqrt(3);
Zl = 2 + j*4; Z1 = 30 + j*40;
Z2 = (60-j*45)/3;
Z = Zl + Z1*Z2/(Z1+Z2);
I=V1/Z, S=3*V1*conj(I)
V2 = V1- Zl*I
V2ab =sqrt(3)*(cos(pi/6)+j*sin(pi/6))*V2
I1=V2/Z1, I2=V2/Z2
Iab=I2/(sqrt(3)*(cos(pi/6)-j*sin(pi/6)))
S1=3*V2*conj(I1), S2=3*V2*conj(I2)
SL = 3*Zl*abs(I)^2
結果
I = 5.0001
S =1.8001e+03
V2 = 1.1000e+02 - 2.0000e+01i
V2ab = 1.8232e+02 + 6.5264e+01i
I1 = 1.0000 - 2.0000i
I2 = 4.0001 + 2.0000i
Iab = 1.4227 + 2.1547i
S1 = 4.5002e+02 + 6.0002e+02i
S2 = 1.2000e+03 - 9.0003e+02i
SL = 1.5001e+02 + 3.0001e+02i
例2.8
V2 = 3810.5/sqrt(3);
Zl = 0.4 +j*2.7;
S1 = 560.1*(cos(pi/4) + j*sin(pi/4)); S2 = 132;
SR = S1+ S2
I = conj(SR)*1000/(3*conj(V2))
V1 = V2 + Zl*I
V1L = sqrt(3)*abs(V1)
SL = 3*Zl*abs(I)^2/1000
SS = 3 *V1*conj(I)/1000
SS = SR + SL
結果
SR = 5.2805e+02 + 3.9605e+02i
I =80.0079 -60.0078i
V1 = 2.3940e+03 + 1.9202e+02i
V1L = 4.1599e+03
SL =12.0026 +81.0179i
SS =5.4005e+02 + 4.7707e+02i
SS =5.4005e+02 + 4.7707e+02i
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