Question
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Solution -- Two Pointers
Remember that p1 starts from -1.
1 public class Solution { 2 public int removeElement(int[] nums, int val) { 3 int length = nums.length; 4 if (length == 0) 5 return 0; 6 if (length == 1) { 7 if (nums[0] == val) 8 return 0; 9 else 10 return 1; 11 } 12 int p1 = -1, p2 = 0; 13 while (p2 < length) { 14 if (nums[p2] != val) { 15 p1++; 16 nums[p1] = nums[p2]; 17 p2++; 18 } else { 19 p2++; 20 } 21 } 22 return p1 + 1; 23 } 24 }