Leetcode - Bitwise AND of Numbers Range
My code:
public class Solution {
public int rangeBitwiseAnd(int m, int n) {
int i = 1;
while (m != n) {
m >>= 1;
n >>= 1;
i <<= 1;
}
return m * i;
}
}
reference:
一開始看了這個最優解
https://discuss.leetcode.com/topic/12133/bit-operation-solution-java
不明白為什麼最後 m * iteration
然後看了這個：
http://www.cnblogs.com/grandyang/p/4431646.html
更加形象，就理解了。
Anyway, Good luck, Richardo! -- 10/14/2016
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