A ramp in an integer array nums is a pair (i, j) for which i < j and nums[i] <= nums[j]. The width of such a ramp is j - i.
Given an integer array nums, return the maximum width of a ramp in nums. If there is no ramp in nums, return 0.
Example 1:
Input: nums = [6,0,8,2,1,5]
Output: 4
Explanation: The maximum width ramp is achieved at (i, j) = (1, 5): nums[1] = 0 and nums[5] = 5.
Example 2:
Input: nums = [9,8,1,0,1,9,4,0,4,1]
Output: 7
Explanation: The maximum width ramp is achieved at (i, j) = (2, 9): nums[2] = 1 and nums[9] = 1.
Constraints:
2 <= nums.length <= 5 * 104
0 <= nums[i] <= 5 * 104
最大寬度坡。
給定一個整數陣列 A,坡是元組 (i, j),其中 i < j 且 A[i] <= A[j]。這樣的坡的寬度為 j - i。找出 A 中的坡的最大寬度,如果不存在,返回 0 。
思路
這道題的思路是單調棧,不過這道題跟一般的單調棧題目有些不同。這道題的單調棧找的是兩個距離最遠的下標。
複雜度
時間O(n)
空間O(n)
程式碼
Java實現
class Solution {
public int maxWidthRamp(int[] nums) {
Deque<Integer> stack = new ArrayDeque<>();
int res = 0;
int n = nums.length;
for (int i = 0; i < n; i++) {
if (stack.isEmpty() || nums[i] < nums[stack.peekLast()]) {
stack.offerLast(i);
}
}
for (int i = n - 1; i > 0; i--) {
while (!stack.isEmpty() && nums[i] >= nums[stack.peekLast()]) {
res = Math.max(res, i - stack.pollLast());
}
}
return res;
}
}