2.13

世梦發表於2024-10-27

def bifurcate_by(L, fn):
return [[x for x in L if fn(x)], [x for x in L if not fn(x)]]
s = bifurcate_by(['beep', 'boop', 'foo', 'bar'], lambda x: x[0] == 'b')
print(s)

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