自本系列第一講推出以來，得到了不少同學的反響和贊成，也有同學留言說最好能把數學推導部分寫的詳細點，筆者只能說盡力，因為打公式實在是太浪費時間了。。本節要和大家一起學習的是邏輯（logistic）迴歸模型，繼續按照手推公式+純 Python 的寫作套路。
邏輯迴歸本質上跟邏輯這個詞不是很搭邊，叫這個名字完全是直譯過來形成的。那該怎麼叫呢？其實邏輯迴歸本名應該叫對數機率迴歸，是線性迴歸的一種推廣，所以我們在統計學上也稱之為廣義線性模型。眾多周知的是，線性迴歸針對的是標籤為連續值的機器學習任務，那如果我們想用線性模型來做分類任何可行嗎？答案當然是肯定的。
sigmoid 函式
相較於線性迴歸的因變數 y 為連續值，邏輯迴歸的因變數則是一個 0/1 的二分類值，這就需要我們建立一種對映將原先的實值轉化為 0/1 值。這時候就要請出我們熟悉的 sigmoid 函式了:
其函式圖形如下：
除了長的很優雅之外，sigmoid 函式還有一個很好的特性就是其求導計算等於下式，這給我們後續求交叉熵損失的梯度時提供了很大便利。
邏輯迴歸模型的數學推導
由 sigmoid 函式可知邏輯迴歸模型的基本形式為：
稍微對上式做一下轉換：
下面將 y 視為類後驗概率 p(y = 1 | x)，則上式可以寫為：
則有：
將上式進行簡單綜合，可寫成如下形式：
寫成對數形式就是我們熟知的交叉熵損失函式了，這也是交叉熵損失的推導由來：
最優化上式子本質上就是我們統計上所說的求其極大似然估計，可基於上式分別關於 W 和b 求其偏導可得：
基於 W 和 b 的梯度進行權值更新即可求導引數的最優值，使得損失函式最小化，也即求得引數的極大似然估計，殊途同歸啊。
邏輯迴歸的 Python 實現
跟上一講寫線性模型一樣，在實際動手寫之前我們需要理清楚思路。要寫一個完整的邏輯迴歸模型我們需要：sigmoid函式、模型主體、引數初始化、基於梯度下降的引數更新訓練、資料測試與視覺化展示。
先定義一個 sigmoid 函式：
import numpy as np
def sigmoid(x):
z = 1 / (1 + np.exp(-x))
return z
複製程式碼定義模型引數初始化函式：
def initialize_params(dims):
W = np.zeros((dims, 1))
b = 0
return W, b
複製程式碼定義邏輯迴歸模型主體部分，包括模型計算公式、損失函式和引數的梯度公式：
def logistic(X, y, W, b):
num_train = X.shape[0]
num_feature = X.shape[1]
a = sigmoid(np.dot(X, W) + b)
cost = -1/num_train * np.sum(y*np.log(a) + (1-y)*np.log(1-a))
dW = np.dot(X.T, (a-y))/num_train
db = np.sum(a-y)/num_train
cost = np.squeeze(cost)
return a, cost, dW, db
複製程式碼定義基於梯度下降的引數更新訓練過程：
def logistic_train(X, y, learning_rate, epochs):
# 初始化模型引數
W, b = initialize_params(X.shape[1])
cost_list = []
# 迭代訓練
for i in range(epochs):
# 計算當前次的模型計算結果、損失和引數梯度
a, cost, dW, db = logistic(X, y, W, b)
# 引數更新
W = W -learning_rate * dW
b = b -learning_rate * db
# 記錄損失
if i % 100 == 0:
cost_list.append(cost)
# 列印訓練過程中的損失
if i % 100 == 0:
print('epoch %d cost %f' % (i, cost))
# 儲存引數
params = {
'W': W,
'b': b
}
# 儲存梯度
grads = {
'dW': dW,
'db': db
}
return cost_list, params, grads
複製程式碼定義對測試資料的預測函式：
def predict(X, params):
y_prediction = sigmoid(np.dot(X, params['W']) + params['b'])
for i in range(len(y_prediction)):
if y_prediction[i] > 0.5:
y_prediction[i] = 1
else:
y_prediction[i] = 0
return y_prediction
複製程式碼使用 sklearn 生成模擬的二分類資料集進行模型訓練和測試：
import matplotlib.pyplot as plt
from sklearn.datasets.samples_generator import make_classification
X,labels=make_classification(n_samples=100, n_features=2, n_redundant=0, n_informative=2, random_state=1, n_clusters_per_class=2)
rng=np.random.RandomState(2)
X+=2*rng.uniform(size=X.shape)
unique_lables=set(labels)
colors=plt.cm.Spectral(np.linspace(0, 1, len(unique_lables)))
for k, col in zip(unique_lables, colors):
x_k=X[labels==k]
plt.plot(x_k[:, 0], x_k[:, 1], 'o', markerfacecolor=col, markeredgecolor="k",
markersize=14)
plt.title('data by make_classification()')
plt.show()
複製程式碼資料分佈展示如下：
對資料進行簡單的訓練集與測試集的劃分：
offset = int(X.shape[0] * 0.9)
X_train, y_train = X[:offset], labels[:offset]
X_test, y_test = X[offset:], labels[offset:]
y_train = y_train.reshape((-1,1))
y_test = y_test.reshape((-1,1))
print('X_train=', X_train.shape)
print('X_test=', X_test.shape)
print('y_train=', y_train.shape)
print('y_test=', y_test.shape)
複製程式碼
對訓練集進行訓練：
cost_list, params, grads = lr_train(X_train, y_train, 0.01, 1000)
複製程式碼迭代過程如下：
對測試集資料進行預測：
y_prediction = predict(X_test, params)
print(y_prediction)
複製程式碼預測結果如下：
定義一個分類準確率函式對訓練集和測試集的準確率進行評估：
def accuracy(y_test, y_pred):
correct_count = 0
for i in range(len(y_test)):
for j in range(len(y_pred)):
if y_test[i] == y_pred[j] and i == j:
correct_count +=1
accuracy_score = correct_count / len(y_test)
return accuracy_score
# 列印訓練準確率
accuracy_score_train = accuracy(y_train, y_train_pred)
print(accuracy_score_train)
複製程式碼
檢視測試集準確率：
accuracy_score_test = accuracy(y_test, y_prediction)
print(accuracy_score_test)
複製程式碼
沒有進行交叉驗證，測試集準確率存在一定的偶然性哈。 最後我們定義個繪製模型決策邊界的圖形函式對訓練結果進行視覺化展示：
def plot_logistic(X_train, y_train, params):
n = X_train.shape[0]
xcord1 = []
ycord1 = []
xcord2 = []
ycord2 = []
for i in range(n):
if y_train[i] == 1:
xcord1.append(X_train[i][0])
ycord1.append(X_train[i][1])
else:
xcord2.append(X_train[i][0])
ycord2.append(X_train[i][1])
fig = plt.figure()
ax = fig.add_subplot(111)
ax.scatter(xcord1, ycord1,s=32, c='red')
ax.scatter(xcord2, ycord2, s=32, c='green')
x = np.arange(-1.5, 3, 0.1)
y = (-params['b'] - params['W'][0] * x) / params['W'][1]
ax.plot(x, y)
plt.xlabel('X1')
plt.ylabel('X2')
plt.show()
plot_logistic(X_train, y_train, params)
複製程式碼
元件封裝成邏輯迴歸類
將以上實現過程使用一個 python 類進行封裝：
import numpy as np
import matplotlib.pyplot as plt
from sklearn.datasets.samples_generator import make_classification
class logistic_regression():
def __init__(self):
pass
def sigmoid(self, x):
z = 1 / (1 + np.exp(-x))
return z
def initialize_params(self, dims):
W = np.zeros((dims, 1))
b = 0
return W, b
def logistic(self, X, y, W, b):
num_train = X.shape[0]
num_feature = X.shape[1]
a = self.sigmoid(np.dot(X, W) + b)
cost = -1 / num_train * np.sum(y * np.log(a) + (1 - y) * np.log(1 - a))
dW = np.dot(X.T, (a - y)) / num_train
db = np.sum(a - y) / num_train
cost = np.squeeze(cost)
return a, cost, dW, db
def logistic_train(self, X, y, learning_rate, epochs):
W, b = self.initialize_params(X.shape[1])
cost_list = []
for i in range(epochs):
a, cost, dW, db = self.logistic(X, y, W, b)
W = W - learning_rate * dW
b = b - learning_rate * db
if i % 100 == 0:
cost_list.append(cost)
if i % 100 == 0:
print('epoch %d cost %f' % (i, cost))
params = {
'W': W,
'b': b
}
grads = {
'dW': dW,
'db': db
}
return cost_list, params, grads
def predict(self, X, params):
y_prediction = self.sigmoid(np.dot(X, params['W']) + params['b'])
for i in range(len(y_prediction)):
if y_prediction[i] > 0.5:
y_prediction[i] = 1
else:
y_prediction[i] = 0
return y_prediction
def accuracy(self, y_test, y_pred):
correct_count = 0
for i in range(len(y_test)):
for j in range(len(y_pred)):
if y_test[i] == y_pred[j] and i == j:
correct_count += 1
accuracy_score = correct_count / len(y_test)
return accuracy_score
def create_data(self):
X, labels = make_classification(n_samples=100, n_features=2, n_redundant=0, n_informative=2, random_state=1, n_clusters_per_class=2)
labels = labels.reshape((-1, 1))
offset = int(X.shape[0] * 0.9)
X_train, y_train = X[:offset], labels[:offset]
X_test, y_test = X[offset:], labels[offset:]
return X_train, y_train, X_test, y_test
def plot_logistic(self, X_train, y_train, params):
n = X_train.shape[0]
xcord1 = []
ycord1 = []
xcord2 = []
ycord2 = []
for i in range(n):
if y_train[i] == 1:
xcord1.append(X_train[i][0])
ycord1.append(X_train[i][1])
else:
xcord2.append(X_train[i][0])
ycord2.append(X_train[i][1])
fig = plt.figure()
ax = fig.add_subplot(111)
ax.scatter(xcord1, ycord1, s=32, c='red')
ax.scatter(xcord2, ycord2, s=32, c='green')
x = np.arange(-1.5, 3, 0.1)
y = (-params['b'] - params['W'][0] * x) / params['W'][1]
ax.plot(x, y)
plt.xlabel('X1')
plt.ylabel('X2')
plt.show()
if __name__ == "__main__":
model = logistic_regression()
X_train, y_train, X_test, y_test = model.create_data()
print(X_train.shape, y_train.shape, X_test.shape, y_test.shape)
cost_list, params, grads = model.logistic_train(X_train, y_train, 0.01, 1000)
print(params)
y_train_pred = model.predict(X_train, params)
accuracy_score_train = model.accuracy(y_train, y_train_pred)
print('train accuracy is:', accuracy_score_train)
y_test_pred = model.predict(X_test, params)
accuracy_score_test = model.accuracy(y_test, y_test_pred)
print('test accuracy is:', accuracy_score_test)
model.plot_logistic(X_train, y_train, params)
複製程式碼好了，關於邏輯迴歸的內容，筆者就介紹到這，至於如何在實戰中檢驗邏輯迴歸的分類效果，還需各位親自試一試。多說一句，邏輯迴歸模型與感知機、神經網路和深度學習有著千絲萬縷的關係，作為基礎的機器學習模型，希望大家能夠牢固掌握其數學推導和手動實現方式，在此基礎上再去呼叫 sklearn 中的 LogisticRegression 模組，必能必能裨補闕漏，有所廣益。
參考資料：