Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
confused what "{1,#,2,3}"
means? > read more on how binary tree is serialized on OJ.
注意本題在原有的函式上新增了預設引數,以便形成遞迴
class Solution { public: bool isValidBST(TreeNode *root,int min = INT_MIN,int max = INT_MAX){ if(!root) return true; if(root->val <= min || root->val>=max) return false; return isValidBST(root->left,min,root->val) && isValidBST(root->right,root->val, max); } };