Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / \ 2 3 \ 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.
Solution:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public List<String> binaryTreePaths(TreeNode root) { List<String> resList = new LinkedList<String>(); StringBuilder builder = new StringBuilder(); binaryTreePaths(root,builder,resList); return resList; } public void binaryTreePaths(TreeNode cur, StringBuilder builder, List<String> resList){ if (cur==null){ return; } builder.append(cur.val); if (cur.left==null && cur.right==null){ resList.add(builder.toString()); return; } builder.append("->"); int len = builder.length(); binaryTreePaths(cur.left,builder,resList); builder.setLength(len); binaryTreePaths(cur.right,builder,resList); } }