Programming Languages_05 FWAE

界內嘻哈發表於2020-05-06

FWAE : Concrete syntax

<FWAE> ::= <num>
         | {+ <FWAE> <FWAE>}
         | {- <FWAE> <FWAE>}
         | {with {<id> <FWAE>} <FWAE>}
         | <id>
         | {fun {<id>} <FWAE>}
         | {<FWAE> <FWAE>}

FWAE : Abstract syntax

其中的“function definition”和“function call”在language structure內以lambda函式形式包含在其中，所以不需要像F1WAE那樣的FunDef。
(define-type FWAE
  [num (n number?)]
  [add (lhs FWAE?) (rhs FWAE?)]
  [sub (lhs FWAE?) (rhs FWAE?)]
  [with (name symbol?) (named-expr FWAE?) (body FWAE?)]
  [id (name symbol?)]
  [fun (param symbol?) (body FWAE?)]
  [app (ftn FWAE?) (arg FWAE?)])
(fun x (add 1 x))等lambda函式形態本身就是with-namd-expr的FWAE∼ae型別，那麼在with-body中，與with-name一致的相應id被調換到fun，並進入app的ftn之中。

parse : sexp -> FWAE

(define (parse sexp)
  (match sexp
    [(? number?) (num sexp)]
    [(list '+ l r) (add (parse l) (parse r))]
    [(list '- l r) (sub (parse l) (parse r))]
    [(list 'with (list x i) b) (with x (parse i) (parse b))]
    [(? symbol?) (id sexp)]
    [(list 'fun (list x) b) (fun x (parse b))]
    [(list f a) (app (parse f) (parse a))]
    [else (error 'parse "bad syntax :~a" sexp)]))

interp : FWAE -> FWAE

因為最終的結果是FWAE，所以add和sub的結果會使num重新加入。
(define (num+ x y)
  (num (+ (num-n x) (num-n y))))
(define (num- x y)
  (num (- (num-n x) (num-n y))))
  
(define (interp fwae)
  (type-case FWAE fwae
    [num (n) fwae]
    [add (l r) (num+ (interp l) (interp r))]
    [sub (l r) (num- (interp l) (interp r))]
    [with (x i b) (interp (subst b x (interp i)))]
    [id (s) (error 'interp "free variable")]
    [fun (x b) fwae]
    [app (f a) (local [(define ftn (interp f))]
                  (interp (subst (fun-body ftn)
                                 (fun-param ftn)
                                 (interp a))))]))
app中將ftn作為local define，如果f是未定義的函式，那麼將出現free variable error，如果f是已經定義的函式，那麼就是fun的形態，所以ftn具有fun的structure。

subst : FWAE symbol FWAE -> FWAE

(define (subst exp sub-id val)
  (type-case FWAE exp
    [num (n) exp]
    [add (l r) (add (subst l sub-id val) (subst r sub-id val))]
    [sub (l r) (sub (subst l sub-id val) (subst r sub-id val))]
    [with (x i b) (with x
                        (subst i sub-id val)
                        (if (symbol=? sub-id x)
                            b
                            (subst b sub-id val)))]
    [id (name) (cond [(equal? name sub-id) val]
                     [else exp])]
    [app (f arg) (app (subst f sub-id val)
                      (subst arg sub-id val))]
    [fun (id body) (if (equal? sub-id id)
                       exp
                       (fun id (subst body sub-id val)))]))

Examples

F1WAE : first-order functions
{deffun {f x} {+ 1 x}}
{f 10}

FWAE : first-class functions
{with {f {fun {x} {+ 1 x}}} {f 10}}

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