不會改變操作物件內容的STL演算法(元素查詢,序列查詢,統計元素個數,比較區間,找最值)

readyao發表於2016-01-10

元素查詢,序列查詢,統計元素個數,比較區間,找最值

一、單個元素查詢: find, find_if, adjacent_find, find_first_of

1、find:查詢元素val

template<class InputIterator, class T>
	InputIterator find (InputIterator first, InputIterator last, const T& val)
{
  while (first!=last) {
    if (*first==val) return first;
    ++first;
  }
  return last;
}

2、find_if:查詢滿足pred(*first)條件的元素

template<class InputIterator, class UnaryPredicate>
  InputIterator find_if (InputIterator first, InputIterator last, UnaryPredicate pred)
{
  while (first!=last) {
    if (pred(*first)) return first;
    ++first;
  }
  return last;
}
此時可能的UnaryPredicate有,bind2nd(equal_to<int>(), 0),bind2nd(less<int>(), 0),自定義等

3、adjacent_find:查詢兩個相鄰的元素或者前後兩個元素滿足條件pred(*first,*next)

template <class ForwardIterator>
   ForwardIterator adjacent_find (ForwardIterator first, ForwardIterator last)
{
  if (first != last)
  {
    ForwardIterator next=first; ++next;
    while (next != last) {
      if (*first == *next)     // or: if (pred(*first,*next)), for version (2)
        return first;
      ++first; ++next;
    }
  }
  return last;
}

4、find_first_of:查詢[first1,last1)內第一個等於[first2,last2)內的任意一個元素,或滿足條件pred(*it,*first)的元素

template<class InputIterator, class ForwardIterator>
  InputIterator find_first_of ( InputIterator first1, InputIterator last1,
                                ForwardIterator first2, ForwardIterator last2)
{
  while (first1!=last1) {
    for (ForwardIterator it=first2; it!=last2; ++it) {
      if (*it==*first1)          // or: if (pred(*it,*first)) for version (2)
        return first1;
    }
    ++first1;
  }
  return last1;
}

二、子序列匹配(子序列查詢): search, find_end, search_n

1、search 在區間[first1,last1)查詢第一次出現的子序列[first2,last2)

Searches the range [first1,last1) for the first occurrence of the sequence defined by [first2,last2), and returns an iterator to its first element, or last1 if no occurrences are found.

template<class ForwardIterator1, class ForwardIterator2>
  ForwardIterator1 search ( ForwardIterator1 first1, ForwardIterator1 last1,
                            ForwardIterator2 first2, ForwardIterator2 last2)
{
  if (first2==last2) return first1;  // specified in C++11
  
  while (first1!=last1)
  {
    ForwardIterator1 it1 = first1;
    ForwardIterator2 it2 = first2;
    while (*it1==*it2) {    // or: while (pred(*it1,*it2)) for version 2
        ++it1; ++it2;
        if (it2==last2) return first1;
        if (it1==last1) return last1;
    }
    ++first1;
  }
  return last1;
}

2、find_end 在區間[first1,last1)查詢最後一次出現的子序列[first2,last2)

這個函式名字有點問題,不應該和find歸在一起,應該是search_end
Searches the range [first1,last1) for the last occurrence of the sequence defined by [first2,last2), and returns an iterator to its first element, or last1 if no occurrences are found.

template<class ForwardIterator1, class ForwardIterator2>
  ForwardIterator1 find_end (ForwardIterator1 first1, ForwardIterator1 last1,
                             ForwardIterator2 first2, ForwardIterator2 last2)
{
  if (first2==last2) return last1;  // specified in C++11

  ForwardIterator1 ret = last1;

  while (first1!=last1)
  {
    ForwardIterator1 it1 = first1;
    ForwardIterator2 it2 = first2;
    while (*it1==*it2) {    // or: while (pred(*it1,*it2)) for version (2)
        ++it1; ++it2;
        if (it2==last2) { ret=first1; break; }
        if (it1==last1) return ret;
    }
    ++first1;
  }
  return ret;
}

3、search_n 查詢區間[first,last)中由count個相鄰元素形成的子序列,其中所有元素都等於value

Searches the range [first,last) for a sequence of count elements, each comparing equal to val (or for which pred returns true).

template<class ForwardIterator, class Size, class T>
  ForwardIterator search_n (ForwardIterator first, ForwardIterator last,
                            Size count, const T& val)
{
  ForwardIterator it, limit;
  Size i;

  limit=first; std::advance(limit,std::distance(first,last)-count);

  while (first!=limit)
  {
    it = first; i=0;
    while (*it==val)       // or: while (pred(*it,val)) for the pred version
      { ++it; if (++i==count) return first; }
    ++first;
  }
  return last;
}

三、計算區間中某個元素個數:count, count_if

1、count:計算區間[first,last)中和val相等的元素的個數

template <class InputIterator, class T>
  typename iterator_traits<InputIterator>::difference_type
    count (InputIterator first, InputIterator last, const T& val)
{
  typename iterator_traits<InputIterator>::difference_type ret = 0;
  while (first!=last) {
    if (*first == val) ++ret;
    ++first;
  }
  return ret;
}

2、count_if:計算區間[first,last)中滿足條件pred(*first)的元素的個數

template <class InputIterator, class UnaryPredicate>
  typename iterator_traits<InputIterator>::difference_type
    count (InputIterator first, InputIterator last, UnaryPredicate pred)
{
  typename iterator_traits<InputIterator>::difference_type ret = 0;
  while (first!=last) {
    if (pred(*first)) ++ret;
    ++first;
  }
  return ret;
}

此時可能的UnaryPredicate有,bind2nd(equal_to<int>(), 0),bind2nd(less<int>(), 0),自定義等

四、for_each遍歷區間[first,last)中的每個元素並將Function fn套用在每個元素上

template<class InputIterator, class Function>
  Function for_each(InputIterator first, InputIterator last, Function fn)
{
  while (first!=last) {
    fn (*first);
    ++first;
  }
  return fn;      // or, since C++11: return move(fn);
}

五:比較兩個區間:equal, mismatch, lexicographical_compare

1、equal:當區間[first1,last1)中的元素和區間[first2,first2+(last1-first1))一一比較,如果都相等或滿足pred(*first1,*first2)條件,則返回true,否則返回false

template <class InputIterator1, class InputIterator2>
  bool equal ( InputIterator1 first1, InputIterator1 last1, InputIterator2 first2 )
{
  while (first1!=last1) {
    if (!(*first1 == *first2))   // or: if (!pred(*first1,*first2)), for version 2
      return false;
    ++first1; ++first2;
  }
  return true;
}

2、mismatch:返回區間[first1,last1)中的元素和區間[first2,first2+(last1-first1))之間第一個元素值不同的位置(有兩個位置,每個區間一個)

template <class InputIterator1, class InputIterator2>
  pair<InputIterator1, InputIterator2>
    mismatch (InputIterator1 first1, InputIterator1 last1, InputIterator2 first2 )
{
  while ( (first1!=last1) && (*first1==*first2) )  // or: pred(*first1,*first2), for version 2
  { ++first1; ++first2; }
  return std::make_pair(first1,first2);
}

3、lexicographical_compare:以字典排序法比較,[first1,last1)小於[first2,last2)的話,返回true,否則返回false

template <class InputIterator1, class InputIterator2>
  bool lexicographical_compare (InputIterator1 first1, InputIterator1 last1,
                                InputIterator2 first2, InputIterator2 last2);
 
template <class InputIterator1, class InputIterator2, class Compare>
  bool lexicographical_compare (InputIterator1 first1, InputIterator1 last1,
                                InputIterator2 first2, InputIterator2 last2,
                                Compare comp); 

template <class InputIterator1, class InputIterator2>
  bool lexicographical_compare (InputIterator1 first1, InputIterator1 last1,
                                InputIterator2 first2, InputIterator2 last2)
{
  while (first1!=last1)
  {
    if (first2==last2 || *first2<*first1) return false;
    else if (*first1<*first2) return true;
    ++first1; ++first2;
  }
  return (first2!=last2);
}

六:最大值和最小值:min, max, min_element, max_element

1、min:返回兩個物件a, b之間比較小的那個或滿足!comp(b,a)?a:b;

template <class T> const T& min (const T& a, const T& b) {
  return !(b<a)?a:b;     // or: return !comp(b,a)?a:b; for version (2)
}

2、max:返回兩個物件a, b之間比較大的那個或滿足!comp(b,a)?a:b;

template <class T> const T& max (const T& a, const T& b) {
  return (a<b)?b:a;     // or: return comp(a,b)?b:a; for version (2)
}

3、min_element:找到區間[first,last)內最小的元素

template <class ForwardIterator>
  ForwardIterator min_element ( ForwardIterator first, ForwardIterator last )
{
  if (first==last) return last;
  ForwardIterator smallest = first;

  while (++first!=last)
    if (*first<*smallest)    // or: if (comp(*first,*smallest)) for version (2)
      smallest=first;
  return smallest;
}

4、max_element:找到區間[first,last)內最大的元素

template <class ForwardIterator>
  ForwardIterator max_element ( ForwardIterator first, ForwardIterator last )
{
  if (first==last) return last;
  ForwardIterator largest = first;

  while (++first!=last)
    if (*largest<*first)    // or: if (comp(*largest,*first)) for version (2)
      largest=first;
  return largest;
}

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