Problem
Given an array of integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k.
Example 1:
Input:nums = [1,1,1], k = 2
Output: 2
Note:
The length of the array is in range [1, 20,000].
The range of numbers in the array is [-1000, 1000] and the range of the integer k is [-1e7, 1e7].
Solution
class Solution {
public int subarraySum(int[] nums, int k) {
int sum = 0, res = 0;
Map<Integer, Integer> map = new HashMap<>();
map.put(0, 1);
int preSum = 0;
for (int i = 0; i < nums.length; i++) {
sum += nums[i];
preSum = sum-k;
if (map.containsKey(preSum)) {
res += map.get(preSum);
}
map.put(sum, map.getOrDefault(sum, 0)+1);
}
return res;
}
}
//1, 2, 3, 4, 5, 6 k = 5
//1, 3, 6, 10, 15, 21
//1, 1, 1, 2, 1, 2, 1 k = 3
//1, 2, 3, 5, 6, 8, 9
//1, 2, 0, -1, 0, 1 k = 2
//1, 3, 3, 2, 2, 3