在物件記憶體佈局 (5)的程式碼中,在Derived類中覆蓋Base1中宣告的vfBase1_1(),其他程式碼不變。修改後的程式碼如下:
#include <iostream> using namespace std; class Base1 { public: int m_base1; inline virtual void vfBase1_1() { cout << "This is in Base1::vfBase1_1()" << endl; } inline virtual void vfBase1_2() { cout << "This is in Base1::vfBase1_2()" << endl; } }; class Base2 { public: int m_base2; inline virtual void vfBase2_1() { cout << "This is in Base2::vfBase2_1()" << endl; } inline virtual void vfBase2_2() { cout << "This is in Base2::vfBase2_2()" << endl; } }; class Base3 { public: int m_Base3; inline virtual void vfBase3_1() { cout << "This is in Base3::vfBase3_1()" << endl; } inline virtual void vfBase3_2() { cout << "This is in Base3::vfBase3_2()" << endl; } }; class Derived : public Base1, public Base2, public Base3 { public: int m_derived; inline virtual void fd() { cout << "This is in Derived::fd()" << endl; } inline void vfBase1_1() { cout << "This is in Derived::vfBase1_1()" << endl; } }; typedef void (*VFun)(void); template<typename T> VFun virtualFunctionPointer(T* b, int i) { return (VFun)(*((int*)(*(int*)b) + i)); } int main(void) { Derived d; cout << "The size of Derived object = \t" << sizeof(Derived) << endl; cout << endl; cout << "1st virtual function table: " << endl; int i = 0; while(virtualFunctionPointer(&d, i)&&i<3) { VFun pVF = virtualFunctionPointer(&d, i++); pVF(); } cout << endl; cout << "2nd virtual function table: " << endl; i = 0; //以32字長的機器,找到下一個繼承base class的vptr int* tmp = ((int*)&d)+sizeof(Base1)/4; //虛擬函式表中的虛擬函式後面不為NULL?如果不加i的限制會出現段錯誤,不能結束迴圈 while(virtualFunctionPointer(tmp, i)&&i<2) { VFun pVF = virtualFunctionPointer(tmp, i++); pVF(); } cout << endl; cout << "3rd virtual function table: " << endl; i = 0; tmp = ((int*)&d) + sizeof(Base2)/4; while(virtualFunctionPointer(tmp, i)&&i<2) { VFun pVF = virtualFunctionPointer(tmp, i++); pVF(); } return 0; }
執行結果:
Derived物件值memory layout圖解如下:
我們可以看到,在Derived中overriden的虛擬函式Derived::vfBase1_1排在第一個虛擬函式表的第一位。虛擬函式Base::vfBase1_1()由於已經被overridden,所以在Derived物件的虛擬函式表中不再出現。