火星座標轉換

weixin_33782386發表於2017-09-25

新建一個工具類

PS : 不要問我為什麼,網上找的,忘了那篇文章了,忘記儲存連結了.粘上原始碼

.h檔案

#import <Foundation/Foundation.h>
#import <MapKit/MapKit.h>

@interface WGS84TOGCJ02 : NSObject
+ (CLLocationCoordinate2D)transformFromWGSToGCJ:(CLLocationCoordinate2D)wgsLoc;
@end

.m檔案

#import "WGS84TOGCJ02.h"

const double a = 6378245.0;
const double ee = 0.00669342162296594323;
const double pi = 3.14159265358979324;

@implementation WGS84TOGCJ02

+(CLLocationCoordinate2D)transformFromWGSToGCJ:(CLLocationCoordinate2D)wgsLoc
{
    CLLocationCoordinate2D adjustLoc;
    
    double adjustLat = [self transformLatWithX:wgsLoc.longitude - 105.0 withY:wgsLoc.latitude - 35.0];
    double adjustLon = [self transformLonWithX:wgsLoc.longitude - 105.0 withY:wgsLoc.latitude - 35.0];
    double radLat = wgsLoc.latitude / 180.0 * pi;
    double magic = sin(radLat);
    magic = 1 - ee * magic * magic;
    double sqrtMagic = sqrt(magic);
    adjustLat = (adjustLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
    adjustLon = (adjustLon * 180.0) / (a / sqrtMagic * cos(radLat) * pi);
    adjustLoc.latitude = wgsLoc.latitude + adjustLat;
    adjustLoc.longitude = wgsLoc.longitude + adjustLon;
    
    return adjustLoc;
}

+(double)transformLatWithX:(double)x withY:(double)y
{
    double lat = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * sqrt(fabs(x));
    lat += (20.0 * sin(6.0 * x * pi) + 20.0 *sin(2.0 * x * pi)) * 2.0 / 3.0;
    lat += (20.0 * sin(y * pi) + 40.0 * sin(y / 3.0 * pi)) * 2.0 / 3.0;
    lat += (160.0 * sin(y / 12.0 * pi) + 320 * sin(y * pi / 30.0)) * 2.0 / 3.0;
    return lat;
}

+(double)transformLonWithX:(double)x withY:(double)y
{
    double lon = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(fabs(x));
    lon += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0;
    lon += (20.0 * sin(x * pi) + 40.0 * sin(x / 3.0 * pi)) * 2.0 / 3.0;
    lon += (150.0 * sin(x / 12.0 * pi) + 300.0 * sin(x / 30.0 * pi)) * 2.0 / 3.0;
    return lon;
}

@end

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