Exercise2.78
The internal procedures in the scheme-number package are essentially nothing more than calls to the primitive procedures +, -, etc. It was not possible to use the primitives of the language directly because our type-tag system requires that each data object have a type attached to it. In fact, however, all Lisp implementations do have a type system, which they use internally. Primitive predicates such as symbol? and number? determine whether data objects have particular types. Modify the definitions of type-tag, contents, and attach-tag from Section 2.4.2 so that our generic system takes advantage of Scheme’s internal type system. That is to say, the system should work as before except that ordinary numbers should be represented simply as Scheme numbers rather than as pairs whose car is the symbol scheme-number.
這道題難度不大,就是說我們在設計程式的時候,先用內建的 number? 函式來判斷,如果確實是數字,那就不用新增 scheme-number 標籤,否則還跟之前一樣。
(define (attach-tag type-tag contents)
(if (number? contents)
contents
(cons type-tag contents)))
(define (type-tag datum)
(cond ((number? datum) 'scheme-number)
((pair? datum) (car datum))
(else (error "Bad tagged datum: TYPE-TAG" datum))))
(define (contents datum)
(cond ((number? datum) datum)
((pair? datum) (cdr datum))
(else (error "Bad tagged datum: CONTENTS" datum))))
上網看了別人的答案後,我發現 install-scheme-number-package 也能做一定簡化,如下所示:
(define (install-scheme-number-package)
(put 'add '(scheme-number scheme-number) +)
(put 'sub '(scheme-number scheme-number) -)
(put 'mul '(scheme-number scheme-number) *)
(put 'div '(scheme-number scheme-number) /)
(put 'make 'scheme-number (lambda (x) (attach-tag 'scheme-number x)))
'done)
(define (make-scheme-number n)
((get 'make 'scheme-number) n))
(install-scheme-number-package)
(define m (make-scheme-number 5))
(define n (make-scheme-number 10))
(add m n)
(sub m n)
(mul m n)
(div m n)
; 執行結果
'done
15
-5
50
1/2