sicp每日一題[2.29]

再思即可發表於2024-09-26

Exercise 2.29

A binary mobile consists of two branches, a left branch and a right branch. Each branch is a rod of a certain length, from which hangs either a weight or another binary mobile. We can represent a binary mobile using compound data by constructing it from two branches (for example, using list):

(define (make-mobile left right)
  (list left right))

A branch is constructed from a length (which must be a number) together with a structure, which may be either a number (representing a simple weight) or another mobile:

(define (make-branch length structure)
  (list length structure))

a. Write the corresponding selectors left-branch and right-branch, which return the branches of a mobile, and branch-length and branch-structure, which return the components of a branch.
b. Using your selectors, define a procedure total-weight that returns the total weight of a mobile.
c. A mobile is said to be balanced if the torque applied by its top-left branch is equal to that applied by its top right branch (that is, if the length of the le rod multiplied by the weight hanging from that rod is equal to the corresponding product for the right side) and if each of the submobiles hanging offits branches is balanced. Design a predicate that tests whether a binary mobile is balanced.
d. Suppose we change the representation of mobiles so that the constructors are

(define (make-mobile left right) (cons left right))
(define (make-branch length structure) 
  (cons length structure))

How much do you need to change your programs to convert to the new representation?


這道題主要是需要理解 mobile 是什麼東西,我感覺它跟槓桿很像,然後就比較好處理了。

; a
(define (left-branch mobile)
  (car mobile))

(define (right-branch mobile)
  (car (cdr mobile)))

(define (branch-length branch)
  (car branch))

(define (branch-structure branch)
  (car (cdr branch)))

; b
(define (total-weight mobile)
  (cond ((null? mobile) 0)
        ((not (pair? mobile)) mobile)
        (else (+ (total-weight (branch-structure (left-branch mobile)))
                 (total-weight (branch-structure (right-branch mobile)))))))

; c
(define (torque branch)
  (* (branch-length branch)
     (total-weight (branch-structure branch))))

(define (balanced? mobile)
  (if (not (pair? mobile))
      true
      (= (torque (left-branch mobile))
         (torque (right-branch mobile)))))

(newline)
(define a (make-mobile (make-branch 2 3) (make-branch 3 2)))
(total-weight a)
(balanced? a)

(newline)
(define b (make-mobile (make-branch 2 a) (make-branch 4 a)))
(total-weight b)
(balanced? b)

(newline)
(define c (make-mobile (make-branch 2 b) (make-branch 3 a)))
(total-weight c)
(balanced? c)

; 執行結果
5
#t

10
#f

15
#f

; d
(define (right-branch mobile)
  (cdr mobile))

(define (branch-structure branch)
  (cdr branch))

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