Leetcode 7 Reverse Integer

HowieLee59發表於2018-10-02

Given a 32-bit signed integer, reverse digits of an integer.

Example 1:

Input: 123
Output: 321

Example 2:

Input: -123
Output: -321

Example 3:

Input: 120
Output: 21

Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

class Solution {
    public int reverse(int x) {
        int result = 0;
        while (x != 0) {
            int mod = x % 10;
            x = x / 10;
            if (result > Integer.MAX_VALUE / 10 || result < Integer.MIN_VALUE / 10) return 0;
            result = result * 10 + mod;
        }
        return result;
    }
}

為了防止溢位,在運算中應該加以判斷進行標記,如果溢位那麼直接返回。

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