LeetCode-Wiggle Subsequence

LiBlog發表於2016-07-28

A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A sequence with fewer than two elements is trivially a wiggle sequence.

For example, [1,7,4,9,2,5] is a wiggle sequence because the differences (6,-3,5,-7,3) are alternately positive and negative. In contrast, [1,4,7,2,5] and [1,7,4,5,5] are not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.

Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original order.

Examples:

Input: [1,7,4,9,2,5]
Output: 6
The entire sequence is a wiggle sequence.

Input: [1,17,5,10,13,15,10,5,16,8]
Output: 7
There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8].

Input: [1,2,3,4,5,6,7,8,9]
Output: 2

Follow up:
Can you do it in O(n) time?

Analysis:

Not hard, the longest wiggle subsequence is the sequence composed of all polar points. NOTE: be careful with corner cases: equal nums, all equal nums.

Solution:

 1 public class Solution {
 2     public int getDirect(int curNum, int nextNum){
 3         return (curNum-nextNum)/Math.abs(curNum-nextNum);
 4     }
 5     public int wiggleMaxLength(int[] nums) {
 6         if (nums.length <=1 ) return nums.length;
 7 
 8         int res = 0;
 9         int curInd = 0;
10         int nextInd = 0;
11         while (nextInd < nums.length && nums[curInd] == nums[nextInd]) nextInd++;
12         if (nextInd >= nums.length) return res+1;
13 
14         int preDirect = getDirect(nums[nextInd],nums[curInd]);
15         while (nextInd < nums.length){
16             int curDirect = getDirect(nums[curInd],nums[nextInd]);
17             if (curDirect != 0 && curDirect != preDirect){
18                 res++;
19                 preDirect = curDirect;
20             }
21             curInd++;
22             while (nextInd < nums.length && nums[curInd] == nums[nextInd]) nextInd++;
23         }
24         return res+1;
25     }
26 }

 

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