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demos
leetcode
function subarraysDivByK(nums: number[], k: number): number {
const map = new Map<number, number>();
map.set(0, 1);
let sum = 0;
let count = 0;
let remainder = 0;
for (let num of nums) {
sum += num;
// ???
remainder = ((sum % k) + k) % k;
if (map.has(remainder)) {
count += map.get(remainder)!;
}
map.set(remainder, (map.get(remainder) || 0) + 1);
}
return count;
};
// function subarraysDivByK(nums: number[], k: number): number {
// // -5 / 0 / 5
// let count: number = 0;
// // 單個元素
// for(let i = 0; i < nums.length; i++) {
// if(Math.abs(nums[i] % k) === 0) {
// // console.log(`✅ nums[i] =`, nums[i])
// count += 1;
// }
// }
// // 多個元素
// let i = 0;
// let j = 0;
// let remainder = 0;
// for(i; i < nums.length - 1; i++) {
// remainder = nums[i];
// // console.log(`✅ sum =`, sum)
// // reminder 提醒 ❌
// // remainder 餘數 ✅
// for(j = i + 1; j < nums.length; j++) {
// remainder = (remainder + nums[j]) % k;
// // console.log(`❌ sum =`, sum)
// if(Math.abs(remainder) === 0) {
// count += 1;
// }
// }
// }
// return count;
// };
/*
Time Limit Exceeded
66 / 73 testcases passed
nums =
[0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0]
k =
10000
*/
// function subarraysDivByK(nums: number[], k: number): number {
// // -5 / 0 / 5
// let count: number = 0;
// // 單個元素
// for(let i = 0; i < nums.length; i++) {
// if(Math.abs(nums[i] % k) === 0) {
// // console.log(`✅ nums[i] =`, nums[i])
// count += 1;
// }
// }
// // 多個元素
// let i = 0;
// let j = 0;
// let sum = 0;
// for(i; i < nums.length - 1; i++) {
// sum = nums[i];
// // console.log(`✅ sum =`, sum)
// for(j = i + 1; j < nums.length; j++) {
// sum += nums[j];
// // console.log(`❌ sum =`, sum)
// if(Math.abs(sum % k) === 0) {
// count += 1;
// }
// }
// }
// return count;
// };
// function subarraysDivByK(nums: number[], k: number): number {
// // -5 / 0 / 5
// let i = 0;
// let j = 0;
// let sum = 0;
// let result = [];
// let temp = [];
// for(let i = 0; i < nums.length; i++) {
// if(Math.abs(nums[i] % k) === 0) {
// result.push([nums[i]]);
// }
// }
// for(i; i < nums.length - 1; i++) {
// // if(Math.abs(nums[i] % k) === 0) {
// // console.log(`✅ nums[i] =`, nums[i]);
// // result.push([nums[i]]);
// // console.log(`❓ result =`, result);
// // }
// temp = [];
// j = i + 1;
// temp.push(nums[i])
// for(j; j < nums.length; j++) {
// temp.push(nums[j])
// sum = temp.reduce((s, item) => s += item, 0);
// if(Math.abs(sum % k) === 0) {
// result.push(temp);
// // break;
// }
// console.log(`🚀 result =`, result, j);
// }
// // console.log(`🚀 result =`, result, j);
// }
// console.log(`❌ result =`, result);
// return result.length;
// };
/*
Output Limit Exceeded
38 / 73 testcases passed
nums =
[0,0,0,0,0,0,0,
....
,0,0,0,0,0,0,0]
k =
1000
*/
https://leetcode.com/problems/subarray-sums-divisible-by-k/editorial/?source=submission-ac
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refs
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