sql 經典面試題及答案(選課表)

LifeIsLikeAPlay發表於2018-08-09

SQL資料庫面試題以及答案

Student(Sno,Sname,Sage,Ssex) 學生表       Sno:學號;Sname:學生姓名;Sage:學生年齡;Ssex:學生性別
Course(Cno,Cname,Tno) 課程表                    Cno,課程編號;Cname:課程名字;Tno:教師編號
SC(Sno,Cno,score) 成績表                             Sno:學號;Cno,課程編號;score:成績
Teacher(Tno,Tname) 教師表                        Tno:教師編號; Tname:教師名字

 

建立資料表:

create table Student(

Sno varchar(10) not null primary key,

Sname varchar(20) null,

Sage int null,

Ssex varchar(2) null

)

create table Course(

Cno varchar(10) not null primary key,

Cname varchar(20) null,

Tno varchar(20) null

)

create table SC(

Sno varchar(10) not null primary key,

Cno varchar(10) not null primary key,

score int null

)

create table Teacher(

Tno varchar(20) primary key not null,

Tname varchar(20) null

)

問題:
1、查詢“001”課程比“002”課程成績高的所有學生的學號;
  select a.Sno from (select Sno,score from SC where Cno=`001`) a,(select Sno,score
  from SC where Cno=`002`) b
  where a.score>b.score and a.Sno=b.Sno;
2、查詢平均成績大於60分的同學的學號和平均成績;
    select Sno,avg(score)
    from sc
    group by Sno having avg(score) >60;
3、查詢所有同學的學號、姓名、選課數、總成績;
  select Student.Sno,Student.Sname,count(SC.Cno),sum(score)
  from Student left Outer join SC on Student.Sno=SC.Sno
  group by Student.Sno,Sname
4、查詢姓“李”的老師的個數;
  select count(distinct(Tname))
  from Teacher
  where Tname like `李%`;
5、查詢沒學過“葉平”老師課的同學的學號、姓名;
    select Student.Sno,Student.Sname
    from Student 
    where Sno not in (select distinct( SC.Sno) from SC,Course,Teacher where SC.Cno=Course.Cno and Teacher.Tno=Course.Tno  and Teacher.Tname=`葉平`);
6、查詢學過“001”並且也學過編號“002”課程的同學的學號、姓名;
  select Student.Sno,Student.Sname from Student,SC where Student.Sno=SC.Sno and SC.Cno=`001`and exists( Select * from SC as SC_2 where SC_2.Sno=SC.Sno and SC_2.Cno=`002`);
7、查詢學過“葉平”老師所教的所有課的同學的學號、姓名;
  select Sno,Sname
  from Student
  where Sno in (select Sno from SC ,Course ,Teacher where SC.Cno=Course.Cno and Teacher.Tno=Course.Tno and Teacher.Tname=`葉平` group by Sno having count(SC.Cno)=(select count(Cno) from Course,Teacher  where Teacher.Tno=Course.Tno and Tname=`葉平`));
8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;
  Select Sno,Sname from (select Student.Sno,Student.Sname,score ,(select score from SC SC_2 where SC_2.Sno=Student.Sno and SC_2.Cno=`002`) score2
  from Student,SC where Student.Sno=SC.Sno and Cno=`001`) S_2 where score2 <score;
9、查詢所有課程成績小於60分的同學的學號、姓名;
  select Sno,Sname
  from Student
  where Sno not in (select Student.Sno from Student,SC where S.Sno=SC.Sno and score>60);
10、查詢沒有學全所有課的同學的學號、姓名;
    select Student.Sno,Student.Sname
    from Student,SC
    where Student.Sno=SC.Sno group by  Student.Sno,Student.Sname having count(Cno) <(select count(Cno) from Course);

11、查詢至少有一門課與學號為“1001”的同學所學相同的同學的學號和姓名;
    select Sno,Sname from Student,SC where Student.Sno=SC.Sno and Cno in select Cno from SC where Sno=`1001`;
12、查詢至少學過學號為“001”同學所有一門課的其他同學學號和姓名;
    select distinct SC.Sno,Sname
    from Student,SC
    where Student.Sno=SC.Sno and Cno in (select Cno from SC where Sno=`001`);
13、把“SC”表中“葉平”老師教的課的成績都更改為此課程的平均成績;
    update SC set score=(select avg(SC_2.score)
    from SC SC_2
    where SC_2.Cno=SC.Cno ) from Course,Teacher where Course.Cno=SC.Cno and Course.Tno=Teacher.Tno and Teacher.Tname=`葉平`);
14、查詢和“1002”號的同學學習的課程完全相同的其他同學學號和姓名;
    select Sno from SC where Cno in (select Cno from SC where Sno=`1002`)
    group by Sno having count(*)=(select count(*) from SC where Sno=`1002`);
15、刪除學習“葉平”老師課的SC表記錄;
    Delect SC
    from course ,Teacher 
    where Course.Cno=SC.Cno and Course.Tno= Teacher.Tno and Tname=`葉平`;
16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號“003”課程的同學學號、2、
    號課的平均成績;
    Insert SC select Sno,`002`,(Select avg(score)
    from SC where Cno=`002`) from Student where Sno not in (Select Sno from SC where Cno=`002`);
17、按平均成績從高到低顯示所有學生的“資料庫”、“企業管理”、“英語”三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分
    SELECT Sno as 學生ID
        ,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno=`004`) AS 資料庫
        ,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno=`001`) AS 企業管理
        ,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno=`006`) AS 英語
        ,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績
    FROM SC AS t
    GROUP BY Sno
    ORDER BY avg(t.score) 
18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分
    SELECT L.Cno As 課程ID,L.score AS 最高分,R.score AS 最低分
    FROM SC L ,SC AS R
    WHERE L.Cno = R.Cno and
        L.score = (SELECT MAX(IL.score)
                      FROM SC AS IL,Student AS IM
                      WHERE L.Cno = IL.Cno and IM.Sno=IL.Sno
                      GROUP BY IL.Cno)
        AND
        R.Score = (SELECT MIN(IR.score)
                      FROM SC AS IR
                      WHERE R.Cno = IR.Cno
                  GROUP BY IR.Cno
                    );
19、按各科平均成績從低到高和及格率的百分數從高到低順序
    SELECT t.Cno AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績
        ,100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數
    FROM SC T,Course
    where t.Cno=course.Cno
    GROUP BY t.Cno
    ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查詢如下課程平均成績和及格率的百分數(用”1行”顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)
    SELECT SUM(CASE WHEN Cno =`001` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `001` THEN 1 ELSE 0 END) AS 企業管理平均分
        ,100 * SUM(CASE WHEN Cno = `001` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `001` THEN 1 ELSE 0 END) AS 企業管理及格百分數
        ,SUM(CASE WHEN Cno = `002` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `002` THEN 1 ELSE 0 END) AS 馬克思平均分
        ,100 * SUM(CASE WHEN Cno = `002` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `002` THEN 1 ELSE 0 END) AS 馬克思及格百分數
        ,SUM(CASE WHEN Cno = `003` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `003` THEN 1 ELSE 0 END) AS UML平均分
        ,100 * SUM(CASE WHEN Cno = `003` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `003` THEN 1 ELSE 0 END) AS UML及格百分數
        ,SUM(CASE WHEN Cno = `004` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `004` THEN 1 ELSE 0 END) AS 資料庫平均分
        ,100 * SUM(CASE WHEN Cno = `004` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `004` THEN 1 ELSE 0 END) AS 資料庫及格百分數
  FROM SC
21、查詢不同老師所教不同課程平均分從高到低顯示
  SELECT max(Z.Tno) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.Cno AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績
    FROM SC AS T,Course AS C ,Teacher AS Z
    where T.Cno=C.Cno and C.Tno=Z.Tno
  GROUP BY C.Cno
  ORDER BY AVG(Score) DESC
22、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)
    [學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績
    SELECT  DISTINCT top 3
      SC.Sno As 學生學號,
        Student.Sname AS 學生姓名 ,
      T1.score AS 企業管理,
      T2.score AS 馬克思,
      T3.score AS UML,
      T4.score AS 資料庫,
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分
      FROM Student,SC  LEFT JOIN SC AS T1
                      ON SC.Sno = T1.Sno AND T1.Cno = `001`
            LEFT JOIN SC AS T2
                      ON SC.Sno = T2.Sno AND T2.Cno = `002`
            LEFT JOIN SC AS T3
                      ON SC.Sno = T3.Sno AND T3.Cno = `003`
            LEFT JOIN SC AS T4
                      ON SC.Sno = T4.Sno AND T4.Cno = `004`
      WHERE student.Sno=SC.Sno and
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
      NOT IN
      (SELECT
            DISTINCT
            TOP 15 WITH TIES
            ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
      FROM sc
            LEFT JOIN sc AS T1
                      ON sc.Sno = T1.Sno AND T1.Cno = `k1`
            LEFT JOIN sc AS T2
                      ON sc.Sno = T2.Sno AND T2.Cno = `k2`
            LEFT JOIN sc AS T3
                      ON sc.Sno = T3.Sno AND T3.Cno = `k3`
            LEFT JOIN sc AS T4
                      ON sc.Sno = T4.Sno AND T4.Cno = `k4`
      ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

23、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60]
    SELECT SC.Cno as 課程ID, Cname as 課程名稱
        ,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 – 85]
        ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 – 70]
        ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 – 60]
        ,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
    FROM SC,Course
    where SC.Cno=Course.Cno
    GROUP BY SC.Cno,Cname;

24、查詢學生平均成績及其名次
      SELECT 1+(SELECT COUNT( distinct 平均成績)
              FROM (SELECT Sno,AVG(score) AS 平均成績
                      FROM SC
                  GROUP BY Sno
                  ) AS T1
            WHERE 平均成績 > T2.平均成績) as 名次,
      Sno as 學生學號,平均成績
    FROM (SELECT Sno,AVG(score) 平均成績
            FROM SC
        GROUP BY Sno
        ) AS T2
    ORDER BY 平均成績 desc;
 
25、查詢各科成績前三名的記錄:(不考慮成績並列情況)
      SELECT t1.Sno as 學生ID,t1.Cno as 課程ID,Score as 分數
      FROM SC t1
      WHERE score IN (SELECT TOP 3 score
              FROM SC
              WHERE t1.Cno= Cno
            ORDER BY score DESC
              )
      ORDER BY t1.Cno;
26、查詢每門課程被選修的學生數
  select Cno,count(Sno) from sc group by Cno;
27、查詢出只選修了一門課程的全部學生的學號和姓名
  select SC.Sno,Student.Sname,count(Cno) AS 選課數
  from SC ,Student
  where SC.Sno=Student.Sno group by SC.Sno ,Student.Sname having count(Cno)=1;
28、查詢男生、女生人數
    Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex=`男`;
    Select count(Ssex) as 女生人數 from Student group by Ssex having Ssex=`女`;
29、查詢姓“張”的學生名單
    SELECT Sname FROM Student WHERE Sname like `張%`;
30、查詢同名同性學生名單,並統計同名人數
  select Sname,count(*) from Student group by Sname having  count(*)>1;;
31、1981年出生的學生名單(注:Student表中Sage列的型別是datetime)
    select Sname,  CONVERT(char (11),DATEPART(year,Sage)) as age
    from student
    where  CONVERT(char(11),DATEPART(year,Sage))=`1981`;
32、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列
    Select Cno,Avg(score) from SC group by Cno order by Avg(score),Cno DESC ;
33、查詢平均成績大於85的所有學生的學號、姓名和平均成績
    select Sname,SC.Sno ,avg(score)
    from Student,SC
    where Student.Sno=SC.Sno group by SC.Sno,Sname having    avg(score)>85;
34、查詢課程名稱為“資料庫”,且分數低於60的學生姓名和分數
    Select Sname,isnull(score,0)
    from Student,SC,Course
    where SC.Sno=Student.Sno and SC.Cno=Course.Cno and  Course.Cname=`資料庫`and score <60;
35、查詢所有學生的選課情況;
    SELECT SC.Sno,SC.Cno,Sname,Cname
    FROM SC,Student,Course
    where SC.Sno=Student.Sno and SC.Cno=Course.Cno ;
36、查詢任何一門課程成績在70分以上的姓名、課程名稱和分數;
    SELECT  distinct student.Sno,student.Sname,SC.Cno,SC.score
    FROM student,Sc
    WHERE SC.score>=70 AND SC.Sno=student.Sno;
37、查詢不及格的課程,並按課程號從大到小排列
    select Cno from sc where scor e <60 order by Cno ;
38、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名;
    select SC.Sno,Student.Sname from SC,Student where SC.Sno=Student.Sno and Score>80 and Cno=`003`;
39、求選了課程的學生人數
    select count(*) from sc;
40、查詢選修“葉平”老師所授課程的學生中,成績最高的學生姓名及其成績
    select Student.Sname,score
    from Student,SC,Course C,Teacher
    where Student.Sno=SC.Sno and SC.Cno=C.Cno and C.Tno=Teacher.Tno and Teacher.Tname=`葉平` and SC.score=(select max(score)from SC where Cno=C.Cno );
41、查詢各個課程及相應的選修人數
    select count(*) from sc group by Cno;
42、查詢不同課程成績相同的學生的學號、課程號、學生成績
  select distinct  A.Sno,B.score from SC A  ,SC B where A.Score=B.Score and A.Cno <>B.Cno ;
43、查詢每門功成績最好的前兩名
    SELECT t1.Sno as 學生ID,t1.Cno as 課程ID,Score as 分數
      FROM SC t1
      WHERE score IN (SELECT TOP 2 score
              FROM SC
              WHERE t1.Cno= Cno
            ORDER BY score DESC
              )
      ORDER BY t1.Cno;
44、統計每門課程的學生選修人數(超過10人的課程才統計)。要求輸出課程號和選修人數,查詢結果按人數降序排列,查詢結果按人數降序排列,若人數相同,按課程號升序排列 
    select  Cno as 課程號,count(*) as 人數
    from  sc 
    group  by  Cno
    order  by  count(*) desc,Cno 
45、檢索至少選修兩門課程的學生學號
    select  Sno 
    from  sc 
    group  by  Sno
    having  count(*)  >  =  2
46、查詢全部學生都選修的課程的課程號和課程名
    select  Cno,Cname 
    from  Course 
    where  Cno  in  (select  Cno  from  sc group  by  Cno) 
47、查詢沒學過“葉平”老師講授的任一門課程的學生姓名
    select Sname from Student where Sno not in (select Sno from Course,Teacher,SC where Course.Tno=Teacher.Tno and SC.Cno=course.Cno and Tname=`葉平`);
48、查詢兩門以上不及格課程的同學的學號及其平均成績
    select Sno,avg(isnull(score,0)) from SC where Sno in (select Sno from SC where score <60 group by Sno having count(*)>2)group by Sno;
49、檢索“004”課程分數小於60,按分數降序排列的同學學號
    select Sno from SC where Cno=`004`and score <60 order by score desc;

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