SQL資料庫面試題以及答案
Student(Sno,Sname,Sage,Ssex) 學生表 Sno:學號;Sname:學生姓名;Sage:學生年齡;Ssex:學生性別
Course(Cno,Cname,Tno) 課程表 Cno,課程編號;Cname:課程名字;Tno:教師編號
SC(Sno,Cno,score) 成績表 Sno:學號;Cno,課程編號;score:成績
Teacher(Tno,Tname) 教師表 Tno:教師編號; Tname:教師名字
建立資料表:
create table Student(
Sno varchar(10) not null primary key,
Sname varchar(20) null,
Sage int null,
Ssex varchar(2) null
)
create table Course(
Cno varchar(10) not null primary key,
Cname varchar(20) null,
Tno varchar(20) null
)
create table SC(
Sno varchar(10) not null primary key,
Cno varchar(10) not null primary key,
score int null
)
create table Teacher(
Tno varchar(20) primary key not null,
Tname varchar(20) null
)
問題:
1、查詢“001”課程比“002”課程成績高的所有學生的學號;
select a.Sno from (select Sno,score from SC where Cno=`001`) a,(select Sno,score
from SC where Cno=`002`) b
where a.score>b.score and a.Sno=b.Sno;
2、查詢平均成績大於60分的同學的學號和平均成績;
select Sno,avg(score)
from sc
group by Sno having avg(score) >60;
3、查詢所有同學的學號、姓名、選課數、總成績;
select Student.Sno,Student.Sname,count(SC.Cno),sum(score)
from Student left Outer join SC on Student.Sno=SC.Sno
group by Student.Sno,Sname
4、查詢姓“李”的老師的個數;
select count(distinct(Tname))
from Teacher
where Tname like `李%`;
5、查詢沒學過“葉平”老師課的同學的學號、姓名;
select Student.Sno,Student.Sname
from Student
where Sno not in (select distinct( SC.Sno) from SC,Course,Teacher where SC.Cno=Course.Cno and Teacher.Tno=Course.Tno and Teacher.Tname=`葉平`);
6、查詢學過“001”並且也學過編號“002”課程的同學的學號、姓名;
select Student.Sno,Student.Sname from Student,SC where Student.Sno=SC.Sno and SC.Cno=`001`and exists( Select * from SC as SC_2 where SC_2.Sno=SC.Sno and SC_2.Cno=`002`);
7、查詢學過“葉平”老師所教的所有課的同學的學號、姓名;
select Sno,Sname
from Student
where Sno in (select Sno from SC ,Course ,Teacher where SC.Cno=Course.Cno and Teacher.Tno=Course.Tno and Teacher.Tname=`葉平` group by Sno having count(SC.Cno)=(select count(Cno) from Course,Teacher where Teacher.Tno=Course.Tno and Tname=`葉平`));
8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;
Select Sno,Sname from (select Student.Sno,Student.Sname,score ,(select score from SC SC_2 where SC_2.Sno=Student.Sno and SC_2.Cno=`002`) score2
from Student,SC where Student.Sno=SC.Sno and Cno=`001`) S_2 where score2 <score;
9、查詢所有課程成績小於60分的同學的學號、姓名;
select Sno,Sname
from Student
where Sno not in (select Student.Sno from Student,SC where S.Sno=SC.Sno and score>60);
10、查詢沒有學全所有課的同學的學號、姓名;
select Student.Sno,Student.Sname
from Student,SC
where Student.Sno=SC.Sno group by Student.Sno,Student.Sname having count(Cno) <(select count(Cno) from Course);
11、查詢至少有一門課與學號為“1001”的同學所學相同的同學的學號和姓名;
select Sno,Sname from Student,SC where Student.Sno=SC.Sno and Cno in select Cno from SC where Sno=`1001`;
12、查詢至少學過學號為“001”同學所有一門課的其他同學學號和姓名;
select distinct SC.Sno,Sname
from Student,SC
where Student.Sno=SC.Sno and Cno in (select Cno from SC where Sno=`001`);
13、把“SC”表中“葉平”老師教的課的成績都更改為此課程的平均成績;
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.Cno=SC.Cno ) from Course,Teacher where Course.Cno=SC.Cno and Course.Tno=Teacher.Tno and Teacher.Tname=`葉平`);
14、查詢和“1002”號的同學學習的課程完全相同的其他同學學號和姓名;
select Sno from SC where Cno in (select Cno from SC where Sno=`1002`)
group by Sno having count(*)=(select count(*) from SC where Sno=`1002`);
15、刪除學習“葉平”老師課的SC表記錄;
Delect SC
from course ,Teacher
where Course.Cno=SC.Cno and Course.Tno= Teacher.Tno and Tname=`葉平`;
16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號“003”課程的同學學號、2、
號課的平均成績;
Insert SC select Sno,`002`,(Select avg(score)
from SC where Cno=`002`) from Student where Sno not in (Select Sno from SC where Cno=`002`);
17、按平均成績從高到低顯示所有學生的“資料庫”、“企業管理”、“英語”三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分
SELECT Sno as 學生ID
,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno=`004`) AS 資料庫
,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno=`001`) AS 企業管理
,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno=`006`) AS 英語
,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績
FROM SC AS t
GROUP BY Sno
ORDER BY avg(t.score)
18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分
SELECT L.Cno As 課程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.Cno = R.Cno and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.Cno = IL.Cno and IM.Sno=IL.Sno
GROUP BY IL.Cno)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.Cno = IR.Cno
GROUP BY IR.Cno
);
19、按各科平均成績從低到高和及格率的百分數從高到低順序
SELECT t.Cno AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數
FROM SC T,Course
where t.Cno=course.Cno
GROUP BY t.Cno
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查詢如下課程平均成績和及格率的百分數(用”1行”顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)
SELECT SUM(CASE WHEN Cno =`001` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `001` THEN 1 ELSE 0 END) AS 企業管理平均分
,100 * SUM(CASE WHEN Cno = `001` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `001` THEN 1 ELSE 0 END) AS 企業管理及格百分數
,SUM(CASE WHEN Cno = `002` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `002` THEN 1 ELSE 0 END) AS 馬克思平均分
,100 * SUM(CASE WHEN Cno = `002` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `002` THEN 1 ELSE 0 END) AS 馬克思及格百分數
,SUM(CASE WHEN Cno = `003` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `003` THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN Cno = `003` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `003` THEN 1 ELSE 0 END) AS UML及格百分數
,SUM(CASE WHEN Cno = `004` THEN score ELSE 0 END)/SUM(CASE Cno WHEN `004` THEN 1 ELSE 0 END) AS 資料庫平均分
,100 * SUM(CASE WHEN Cno = `004` AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = `004` THEN 1 ELSE 0 END) AS 資料庫及格百分數
FROM SC
21、查詢不同老師所教不同課程平均分從高到低顯示
SELECT max(Z.Tno) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.Cno AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績
FROM SC AS T,Course AS C ,Teacher AS Z
where T.Cno=C.Cno and C.Tno=Z.Tno
GROUP BY C.Cno
ORDER BY AVG(Score) DESC
22、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)
[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績
SELECT DISTINCT top 3
SC.Sno As 學生學號,
Student.Sname AS 學生姓名 ,
T1.score AS 企業管理,
T2.score AS 馬克思,
T3.score AS UML,
T4.score AS 資料庫,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.Sno = T1.Sno AND T1.Cno = `001`
LEFT JOIN SC AS T2
ON SC.Sno = T2.Sno AND T2.Cno = `002`
LEFT JOIN SC AS T3
ON SC.Sno = T3.Sno AND T3.Cno = `003`
LEFT JOIN SC AS T4
ON SC.Sno = T4.Sno AND T4.Cno = `004`
WHERE student.Sno=SC.Sno and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.Sno = T1.Sno AND T1.Cno = `k1`
LEFT JOIN sc AS T2
ON sc.Sno = T2.Sno AND T2.Cno = `k2`
LEFT JOIN sc AS T3
ON sc.Sno = T3.Sno AND T3.Cno = `k3`
LEFT JOIN sc AS T4
ON sc.Sno = T4.Sno AND T4.Cno = `k4`
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);
23、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60]
SELECT SC.Cno as 課程ID, Cname as 課程名稱
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 – 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 – 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 – 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.Cno=Course.Cno
GROUP BY SC.Cno,Cname;
24、查詢學生平均成績及其名次
SELECT 1+(SELECT COUNT( distinct 平均成績)
FROM (SELECT Sno,AVG(score) AS 平均成績
FROM SC
GROUP BY Sno
) AS T1
WHERE 平均成績 > T2.平均成績) as 名次,
Sno as 學生學號,平均成績
FROM (SELECT Sno,AVG(score) 平均成績
FROM SC
GROUP BY Sno
) AS T2
ORDER BY 平均成績 desc;
25、查詢各科成績前三名的記錄:(不考慮成績並列情況)
SELECT t1.Sno as 學生ID,t1.Cno as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.Cno= Cno
ORDER BY score DESC
)
ORDER BY t1.Cno;
26、查詢每門課程被選修的學生數
select Cno,count(Sno) from sc group by Cno;
27、查詢出只選修了一門課程的全部學生的學號和姓名
select SC.Sno,Student.Sname,count(Cno) AS 選課數
from SC ,Student
where SC.Sno=Student.Sno group by SC.Sno ,Student.Sname having count(Cno)=1;
28、查詢男生、女生人數
Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex=`男`;
Select count(Ssex) as 女生人數 from Student group by Ssex having Ssex=`女`;
29、查詢姓“張”的學生名單
SELECT Sname FROM Student WHERE Sname like `張%`;
30、查詢同名同性學生名單,並統計同名人數
select Sname,count(*) from Student group by Sname having count(*)>1;;
31、1981年出生的學生名單(注:Student表中Sage列的型別是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(char(11),DATEPART(year,Sage))=`1981`;
32、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列
Select Cno,Avg(score) from SC group by Cno order by Avg(score),Cno DESC ;
33、查詢平均成績大於85的所有學生的學號、姓名和平均成績
select Sname,SC.Sno ,avg(score)
from Student,SC
where Student.Sno=SC.Sno group by SC.Sno,Sname having avg(score)>85;
34、查詢課程名稱為“資料庫”,且分數低於60的學生姓名和分數
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.Sno=Student.Sno and SC.Cno=Course.Cno and Course.Cname=`資料庫`and score <60;
35、查詢所有學生的選課情況;
SELECT SC.Sno,SC.Cno,Sname,Cname
FROM SC,Student,Course
where SC.Sno=Student.Sno and SC.Cno=Course.Cno ;
36、查詢任何一門課程成績在70分以上的姓名、課程名稱和分數;
SELECT distinct student.Sno,student.Sname,SC.Cno,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.Sno=student.Sno;
37、查詢不及格的課程,並按課程號從大到小排列
select Cno from sc where scor e <60 order by Cno ;
38、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名;
select SC.Sno,Student.Sname from SC,Student where SC.Sno=Student.Sno and Score>80 and Cno=`003`;
39、求選了課程的學生人數
select count(*) from sc;
40、查詢選修“葉平”老師所授課程的學生中,成績最高的學生姓名及其成績
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.Sno=SC.Sno and SC.Cno=C.Cno and C.Tno=Teacher.Tno and Teacher.Tname=`葉平` and SC.score=(select max(score)from SC where Cno=C.Cno );
41、查詢各個課程及相應的選修人數
select count(*) from sc group by Cno;
42、查詢不同課程成績相同的學生的學號、課程號、學生成績
select distinct A.Sno,B.score from SC A ,SC B where A.Score=B.Score and A.Cno <>B.Cno ;
43、查詢每門功成績最好的前兩名
SELECT t1.Sno as 學生ID,t1.Cno as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.Cno= Cno
ORDER BY score DESC
)
ORDER BY t1.Cno;
44、統計每門課程的學生選修人數(超過10人的課程才統計)。要求輸出課程號和選修人數,查詢結果按人數降序排列,查詢結果按人數降序排列,若人數相同,按課程號升序排列
select Cno as 課程號,count(*) as 人數
from sc
group by Cno
order by count(*) desc,Cno
45、檢索至少選修兩門課程的學生學號
select Sno
from sc
group by Sno
having count(*) > = 2
46、查詢全部學生都選修的課程的課程號和課程名
select Cno,Cname
from Course
where Cno in (select Cno from sc group by Cno)
47、查詢沒學過“葉平”老師講授的任一門課程的學生姓名
select Sname from Student where Sno not in (select Sno from Course,Teacher,SC where Course.Tno=Teacher.Tno and SC.Cno=course.Cno and Tname=`葉平`);
48、查詢兩門以上不及格課程的同學的學號及其平均成績
select Sno,avg(isnull(score,0)) from SC where Sno in (select Sno from SC where score <60 group by Sno having count(*)>2)group by Sno;
49、檢索“004”課程分數小於60,按分數降序排列的同學學號
select Sno from SC where Cno=`004`and score <60 order by score desc;