servlet接收xml資料流[java]

sdvingo發表於2007-03-29

我是這麼收的
BufferedReader reader1 = request.getReader();
InputSource is= new InputSource(reader1);
if(is != null){
System.out.print(readXMLFile(is));
}
else{
System.out.print("no data receive");
}

private String readXMLFile(InputSource in) throws Exception {
Vector student_Vector = new Vector();

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();

DocumentBuilder db = null;

try {

db = dbf.newDocumentBuilder();

} catch (ParserConfigurationException pce) {

System.err.println(pce);

System.exit(1);

}


Document doc = null;

try {

doc = db.parse(in);

} catch (DOMException dom) {

System.err.println(dom.getMessage());

System.exit(1);

} catch (IOException ioe) {

System.err.println(ioe);

System.exit(1);

}
但是收不到

/*********************************************/

public void send(URLConnection connection, String strXml) {

//產生輸出流
BufferedOutputStream out = null;
BufferedInputStream bin=null;
try {
out = new BufferedOutputStream(connection.getOutputStream());

String mob = null;

mob = //strXml;
URLEncoder.encode(strXml, "UTF-8");
out.write(mob.getBytes());
out.flush();

//接受伺服器response的值
bin = new BufferedInputStream(connection.getInputStream());
int len = bin.available();
System.out.println("len:" + len);
byte[] tmp = new byte[len];
bin.read(tmp);
System.out.println("return value:" + new String(tmp));
}
catch (Throwable t) {
t.printStackTrace();
}
}

這個是傳送的

/*****************************************************/

//獲取post資料
public String getDoc(HttpServletRequest request) throws Exception {
char[] readerBuffer = new char[request.getContentLength()];
BufferedReader bufferedReader = request.getReader();
logger.info("開始處理上傳資料");
int portion = bufferedReader.read(readerBuffer);
int amount = portion;
while (amount < readerBuffer.length) {
portion = bufferedReader.read(readerBuffer, amount,
readerBuffer.length - amount);
amount = amount + portion;
}

StringBuffer stringBuffer = new StringBuffer(
(int) (readerBuffer.length * 1.5));
for (int index = 0; index < readerBuffer.length; index++) {
char c = readerBuffer[index];
stringBuffer.append(c);
}

String xml = stringBuffer.toString();
logger.info(xml);
return xml;

}

/*******************************************************/

獲得xml字串後,使用dom4j parse為DOM物件,就可以了。
Document document = DocumentHelper.parseText(xml);

/****************************************************/

InputStream is=request.getInputStream();
DocumentBuilderFactory factory=DocumentBuilderFactory.newInstance();
DocumentBuilder builder=factory.newDocumentBuilder();
Document doc=builder.parse(is);

/***************************************************/

public String urlDecode(String value) {
try {
return java.net.URLDecoder.decode(value, "GB2312");
}
catch (Exception ex) {
ex.printStackTrace();
}

return value;
}
最後亂碼的用這個類搞定了

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