題目連結 | 2130. 連結串列最大孿生和 |
---|---|
思路 | 連結串列綜合題:快慢指標 + 指標翻轉 |
題解連結 | 官方題解 |
關鍵點 | while fast.next and fast.next.next: ... |
時間複雜度 | \(O(n)\) |
空間複雜度 | \(O(1)\) |
程式碼實現:
class Solution:
def pairSum(self, head: Optional[ListNode]) -> int:
if head is None:
return 0
first = self.halfList(head)
second = self.reverseList(first.next)
answer = 0
while second:
answer = max(answer, head.val + second.val)
head = head.next
second = second.next
return answer
def halfList(self, head):
slow = fast = head
while fast.next and fast.next.next:
fast = fast.next.next
slow = slow.next
return slow
def reverseList(self, head):
previous = None
current = head
while current:
next_node = current.next
current.next = previous
previous = current
current = next_node
return previous