9.7 Implement the "paint fill" function that one might see on many image editing programs. That is, given a screen (represented by a two-dimensional array of colors), a point, and a new color, fill in the surrounding area until the color changes from the original color.
這道題是一道填充問題,有點類似於Flash中的油桶工具,就是給指定的位置填充顏色,如果要填充的顏色和原來的顏色相同,則不發生變換,如果不同的話,則把相連線的區域都填充為新的顏色。那麼我們使用遞迴來做,首先判斷要填充的顏色和該位置上原有的顏色是否相同,如果不同的話就開始填充,如果周圍顏色和起始位置顏色相同也填充,參見程式碼如下:
enum Color { Black, White, Red, Yellow, Green }; class Solution { public: bool paintFill(vector<vector<Color> > &screen, int x, int y, Color newColor) { if (screen[x][y] == newColor) return false; return paintFill(screen, x, y, screen[x][y], newColor); } bool paintFill(vector<vector<Color> > &screen, int x, int y, Color oldColor, Color newColor) { if (x < 0 || x >= screen.size() || y < 0 || y >= screen[0].size()) return false; if (screen[x][y] == oldColor) { screen[x][y] = newColor; paintFill(screen, x - 1, y, oldColor, newColor); paintFill(screen, x + 1, y, oldColor, newColor); paintFill(screen, x, y - 1, oldColor, newColor); paintFill(screen, x, y + 1, oldColor, newColor); } return true; } };