【Java】酒店管理系統的模擬

bijian0530發表於2020-11-11

1.先建立一個房間類,屬性為房間號、是否佔用、房間的種類,並建立相應的構造方法。

public class Room {
    private int no;
    private String type;
    private boolean status;

    public Room() {
    }

    public Room (int no, String type, boolean status) {
        this.no = no;
        this.type = type;
        this.status = status;
    }

    public void setNo(int no) {
        this.no = no;
    }

    public void setType(String type) {
        this.type = type;
    }

    public void setStatus(boolean status) {
        this.status = status;
    }

    public int getNo() {
        return no;
    }

    public String getType() {
        return type;
    }

    public boolean isStatus() {
        return status;
    }

重寫Object中的toString方法,並進行測試。

public String toString(){
    return "["+no+","+type+","+(status?"空閒":"佔用")+"]";
}

//測試程式
/*public static void main(String[] args) {
    Room room = new Room(101,"單人間",false);
    System.out.println(room);
}*/

重新Object中的equals方法,並進行測試。

public boolean equals(Object obj){
if(obj == null ||!(obj instanceof Room)) return false;
    if(this == obj) return true;
    Room room = (Room)obj;
    return this.getNo() == room.getNo();
}

/*測試程式
  public static void main(String[] args) {
    Room room = new Room(101,"單人間",false);
    System.out.println(room);
    Room room1 = new Room(101,"單人間",false);
    System.out.println(room.equals(room1));
}
*/

再新增一個Hotel類。建立房間編號,並對相應構造方法進行設定。

public class Hotel {
    private Room[][] rooms;
    public Hotel(){
        rooms = new Room[3][10];
        for(int i = 0; i < rooms.length; i++){
            for(int j = 0; j <rooms[i].length; j++){
                if(i == 0){
                    rooms[i][j] = new Room((i+1)*100+j+1,"單人間",true);
                }
                if(i == 1){
                    rooms[i][j] = new Room((i+1)*100+j+1,"標準間",true);
                }
                if(i ==2){
                    rooms[i][j] = new Room((i+1)*100+j+1,"豪華間",true);
                }
            }
        }
    }

    public Room[][] getRooms() {
        return rooms;
    }

    public void setRooms(Room[][] rooms) {
        this.rooms = rooms;
    }

編寫列印、訂房、退房的方法。

public void print(){
        for(int i=0;i<rooms.length;i++){
            for(int j=0;j<rooms[i].length;j++){
                Room room = rooms[i][j];
                System.out.print(room);
            }
            System.out.println();
        }
    }

    public void order(int roomNo){
        Room room = rooms[roomNo / 100 - 1][roomNo % 100- 1];
        room.setStatus(false);
        System.out.println(roomNo+"已經訂房");
    }

    public void exit(int roomNo){
        Room room = rooms[roomNo / 100 - 1][roomNo % 100-1];
        room.setStatus(true);
        System.out.println(roomNo+"已經退房");
    }
}

建立一個測試程式的主方法。輸入相應的編號表示相應的功能。

import java.util.Scanner;

public class HotelMgtSystem {
    public static void main(String[] args) {
        Hotel hotel = new Hotel();
        System.out.println("歡迎使用酒店管理系統,請認真閱讀相關說明");
        System.out.println("功能對應的編號:[1]檢視房間列表[2]表示訂房[3]表示退房[0]表示提出系統");
        Scanner s = new Scanner(System.in);
        while(true){
            System.out.println("請輸入相關編號");
            int i = s.nextInt();
            if(i == 1){
                hotel.print();
            }
            else if(i == 2){
                System.out.println("請輸入訂房編號");
                int roomNo = s.nextInt();
                hotel.order(roomNo);
            }
            else if(i == 3){
                System.out.println("請輸入退房編號");
                int roomNo = s.nextInt();
                hotel.exit(roomNo);
            }
            else if(i == 0){
                System.out.println("歡迎下次在此光臨");
                return;
            }
            else{
                System.out.println("輸入錯誤,請重新進行輸入");
            }
        }
    }
}

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