javaScript 習題總結(持續更新)

判定偶數

function collect_all_even(collection) {
  return collection.filter(item => item%2 == 0);
}

兩個集合的交集

function get_intersection(collection_a, collection_b) {
  return collection_b.filter(item => collection_a.includes(item))
}

 兩個集合的並集

function get_union(collection_a, collection_b) {
  return new Set([...collection_a,...collection_b]);
}

 升序排序

arr.sort((arr1, arr2) => arr1 - arr2)