模擬MySQL的show grants命令

首先建立使用者,並且將示例帳號的表授權給他。

sqlplus / as sysdba
drop user edmond cascade;
create user edmond identified by edmond;
grant connect,resource to edmond;
grant select,insert,update,delete on hr.employees to edmond;
grant update(department_id),insert(department_name,department_id) on hr.departments to edmond;

作為DBA帳號登入,檢視他的許可權。

set linesize 200;
col privs_type format a10;
col username format a20;
col table_name format a35;
col column_name format a25;
col PRIVILEGE format a60;
with t1 as
(
select upper('edmond') username from dual
)
select '角色' privs_type,'NULL' username,'NULL' table_name,'NULL' column_name,wm_concat(GRANTED_ROLE) PRIVILEGE from dba_role_privs,t1 where GRANTEE=t1.username group by '角色','NULL','NULL','NULL'
union all
select '表許可權',owner,TABLE_NAME,'NULL',wm_concat(PRIVILEGE) PRIVILEGE from dba_tab_privs,t1 where GRANTEE=t1.username group by '表許可權',owner,TABLE_NAME,'NULL'
union all
select '列許可權',owner,TABLE_NAME,column_name,wm_concat(PRIVILEGE) PRIVILEGE from dba_col_privs,t1 where GRANTEE=t1.username group by '列許可權',owner,TABLE_NAME,column_name;

作為普通使用者登入,檢視許可權

set linesize 200;
col privs_type format a10;
col username format a20;
col table_name format a35;
col column_name format a25;
col PRIVILEGE format a60;
with t1 as
(
select upper('edmond') username from dual
)
select '表許可權' privs_type,TABLE_SCHEMA username,TABLE_NAME,'NULL' column_name,wm_concat(PRIVILEGE) PRIVILEGE from all_tab_privs,t1 where GRANTEE=t1.username group by '表許可權',TABLE_SCHEMA,TABLE_NAME,'NULL'
union all
select '列許可權',TABLE_SCHEMA,TABLE_NAME,column_name,wm_concat(PRIVILEGE) PRIVILEGE from all_col_privs,t1 where GRANTEE=t1.username group by '列許可權',TABLE_SCHEMA,TABLE_NAME,column_name;

Oracle檢視使用者許可權

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