動動手:
1. 請用已學過的知識編寫程式,找出小甲魚藏在下邊這個長字串中的密碼,密碼的埋藏點符合以下規律:
a) 每位密碼為單個小寫字母
b) 每位密碼的左右兩邊均有且只有三個大寫字母
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第一次看題,覺得簡單,於是寫出以下程式碼:
- l = len(a)
- for i in range(3, l – 3):
- if a[i].islower():
- for j in range(1, 4):
- if a[i + j].isupper() + a[i – j].isupper() == 2:
- if a[i + 4].isupper() + a[i – 4].isupper() == 0:
- print(a[i], end = “)
結果如下:
- asaazzllqqqpbbiidllmmbbismrrppqqrzpztijjcntjauuiiiooyaasookttqqfaauconeitwwhhoddduaayyvzmoumfaallldubbkkkljlqzqyyarrswvapxmcoqzftzwwhhggfrzzoootvvoyfasgnebxxllvvrrghwsvvvzojbooiwwffyhhptqqzqseeenzmmyxlwwthhodcvyyvjwdccbmtnfcifenpzhhqvwclfffoozzwwowccbstuqivqmtenwwfnqkkvkknaljlegeffccnmeebiisnuuflwkmazookbvtyjpeeddavxxttpprwwiiimmddzzgbooddbbguyiikljdzzvvharxgukyyojtqqcchdlsubnfniuuzzqhljiwdtccfyuunldaagscjsssxtnoysfkhoocxgfuymmcxooqiblufovmddgvjxalhwwdddemtccyyuhqqppddirfyeouuaamznaabnlfphhwzgxuzzaycfewyvqqppvuuwwnnwwyfwwddssjhuppvvmmvvfjdczgkkhuutrjffyvvggvvzfhhhzzaddcczqjxifekxxhpggracllvvivccllppxbthjulrqqggxjuthamgttvjwwgenhvqggkkqceyyhhdfzlyyieruxcbbqqxxjoouuovcrrjnnesjnddazznmhhecffajppzebbppktfdtkkdendnsqqbbcvccchhrivocnfzzvvooeehqxntbbodfiiklritidapgvnnlbffpuvvfifnaddnyuuuaaed
這哪是什麼密碼,簡直就是亂碼,找了半天沒找到原因,死馬當活醫,於是將程式碼修改如下:
- l = len(a)
- for i in range(3, l – 3):
- if a[i].islower():
- if a[i + 1].isupper() + a[i – 1].isupper() == 2:
- if a[i + 2].isupper() + a[i – 2].isupper() == 2:
- if a[i + 3].isupper() + a[i – 3].isupper() == 2:
- if a[i + 4].isupper() + a[i – 4].isupper() == 0:
- print(a[i], end = “)
結果如下:
- ilovefishc
哇噻!竟然對了,這到底是為什麼呢?前後程式碼差不多啊,第一個程式碼相對簡潔啊!為什麼就不對呢?
經過仔細研究,終於找到原因了,這段程式碼的問題在於條件只滿足了兩個條件:
1.小寫字母前後的第4個為小寫字母
2.小寫字母前後的第j個為大寫字母
應該改為小寫字母前後的3個都為大寫字母,直接上程式碼:
1.小寫字母前後的第4個為小寫字母
2.小寫字母前後的第j個為大寫字母
應該改為小寫字母前後的3個都為大寫字母,直接上程式碼:
- l = len(a)
- x = 0
- for i in range(3, l – 3):
- if a[i].islower():
- if a[i + 4].isupper() + a[i – 4].isupper() == 0:
- for j in range(1, 4):
- if a[i + j].isupper() + a[i – j].isupper() == 2:
- x = 1
- else:
- x = 0
- break
- if x == 1:
- print(a[i], end = “)