(轉)PLS_INTEGER型別與timestamp型別、date、及時間函式

mahanso發表於2011-09-01
一、 PLS_INTEGER型別

   今天看到了這個 PLS_INTEGER,覺得生疏,網上搜了下,原來這個型別的好處多多啊。因此將這些轉了過來,收藏了。

PLS_INTEGER可以儲存一個有符號的整形值,其精度範圍和BINARY_INTEGER一樣,是:-2^31~2^31。
PLS_INTEGER和NUMBER比較起來,其優點是:
1).佔有較少的儲存空間;
2).可以直接進行算術運算(在NUMBER上不能直接進行算術運算,如果要計算,NUMBER必須先被轉換成二進位制)。所以在進行算術的時候PLS_INTEGER比NUMBER和BINARY_INTEGER快一些。

PLS_INTEGER和BINARY_INTEGER區別:
PLS_INTEGER進行的運算發生溢位的時候,會觸發異常。但是當BINARY_INTEGER運算發生溢位時,如果可以指派給一個NUMBER變數(沒有超出NUMBER的精度範圍)的話就不會觸發異常。

二、date型別使用

而date型別相減只得到天數
SQL> SELECT sysdate-(sysdate-1) FROM dual;
SYSDATE-(SYSDATE-1)
-------------------
                  1 
 做個試驗:
create table t2 (d1 date,d2 date) ;--建立一個表
INSERT INTO T2 VALUES (SYSDATE, SYSDATE + 1.1234); --插入一條資料

SQL> SELECT D1, D2, D2 - D1, CAST(D2 AS TIMESTAMP) - CAST(D1 AS TIMESTAMP) FROM T2;
D1          D2               D2-D1                  CAST(D2ASTIMESTAMP)-CAST(D1AST
----------- ----------- ---------- ---------------------------------------
2010-12-2 1 2010-12-3 1 1.12340277    +000000001 02:57:42.000000 

date型別相減轉換為天、時分秒
SQL> SELECT TO_NUMBER(SUBSTR(D21, 1, INSTR(D21, ' '))) D,
  2             SUBSTR(D21, INSTR(D21, ' ') + 1, 2) H,
  3             SUBSTR(D21, INSTR(D21, ' ') + 4, 2) M,
  4             SUBSTR(D21, INSTR(D21, ' ') + 7, 2) S
  5      FROM (SELECT CAST(D2 AS TIMESTAMP) - CAST(D1 AS TIMESTAMP) D21
  6             FROM T2) ;
         D H    M    S
---------- ---- ---- ----
         1 02   57   42 

--兩個date日期相減
select dt2 - dt1,
       months_between(dt2, dt1) months_btwn,
       numtodsinterval(dt2 - dt1, 'day') days,
       numtoyminterval(months_between(dt2, dt1), 'month') years_months
  from (select to_date('29-2-2000 01:02:03',
                            'dd-mm-yyyy hh24:mi:ss') dt1,
               to_date('15-3-2001 11:22:33',
                            'dd-mm-yyyy hh24:mi:ss') dt2
          from dual);

--轉換為年,天時分秒
select numtoyminterval(months_between(dt2, dt1), 'month') years_months,
       numtodsinterval(dt2 -
                       add_months(dt1, trunc(months_between(dt2, dt1))),
                       'day') days_hours
  from (select to_date('29-2-2000 01:02:03', 'dd-mm-yyyy hh24:mi:ss') dt1,
               to_date('15-3-2001 11:22:33', 'dd-mm-yyyy hh24:mi:ss') dt2
          from dual);

三、timestamp型別

timestamp 語法:timestamp(n)
--當n=0時,與date長度一樣
create table t (dt date,ts timestamp(0));
insert into t values (sysdate,systimestamp);
SQL> select dump(dt,10) dump,dump(ts,10) dump from t; 
DUMP                                             DUMP
------------------------------------------   ---------------------------------------
Typ=12 Len=7: 120,110,12,4,14,10,10          Typ=180 Len=7: 120,110,12,4,14,10,10

--n為9
create table t (dt date,ts timestamp(9));
insert into t values (sysdate,systimestamp);
SQL> select dump(dt,10) dump,dump(ts,10) dump from t; 
DUMP                                       DUMP
-----------------------------------  --------------------------------------------------------
Typ=12 Len=7: 120,110,12,4,14,7,41        Typ=180 Len=11: 120,110,12,4,14,7,41,11,37,100,192

SQL> select * from t;
DT          TS
----------- -----------------------------------
2010-12-4 1 04-12月-10 01.54.09.625000000 下午  --n為9即秒後面保留的位數(625000000)

select dump(ts,16) dump from t;
Typ=180 Len=11: 78,6e,c,4,e,37,a,25,40,be,40
SQL> select to_number('2540be40','xxxxxxxx') from dual;
 
TO_NUMBER('2540BE40','XXXXXXXX')--將後四個位元組轉換為十進位制
------------------------------
       625000000                --後面四個位元組就是秒小數點後面的數字
       
--timestamp 型別包括了所有DATE資料型別的年月日時分秒的資訊,而且包括了小數秒的資訊
SQL> SELECT sysdate,systimestamp FROM dual;

SYSDATE     SYSTIMESTAMP
----------- ---------------------------------------
2011-3-4 15 04-3月 -11 03.18.16.625000 下午 +08:00

timestamp直接進行加減時會隱式的轉為date型
SQL> select systimestamp ts,systimestamp+1 dt from dual;
 
TS                                                 DT
--------------------------------------------  -----------
04-12月-10 10.40.00.265000 上午 +08:00         2010-12-5 1

解決隱式轉換問題(仍保持timestamp型別)
SQL> select systimestamp ts,systimestamp+numtodsinterval(1,'day') dt from dual;
 
TS                                                       DT
-------------------------------------------- ----------------------------------------------
04-12月-10 10.42.46.515000 上午 +08:00             05-12月-10 10.42.46.515000000 上午 +08:00

兩個timestamp相減
SQL> select dt2 - dt1
  2    from (select to_timestamp('29-2-2000 01:02:03.122000',
  3                              'dd-mm-yyyy hh24:mi:ss.ff') dt1,
  4                 to_timestamp('15-3-2001 11:22:33.000000',
  5                              'dd-mm-yyyy hh24:mi:ss.ff') dt2
  6            from dual);
 
DT2-DT1
---------------------------------------
+000000380 10:20:29.878000000


將其轉換為具體的年、天時分秒
SQL> select numtoyminterval(months_between(dt2, dt1), 'month') years_months,
  2         dt2 - add_months(dt1, trunc(months_between(dt2, dt1))) days_hours
  3    from (select to_timestamp('29-2-2000 01:02:03.122000',
  4                              'dd-mm-yyyy hh24:mi:ss.ff') dt1,
  5                 to_timestamp('15-3-2001 11:22:33.000000',
  6                              'dd-mm-yyyy hh24:mi:ss.ff') dt2
  7            from dual);
 
YEARS_MONTHS                            DAYS_HOURS
--------------------------------------- ---------------------------------------
+000000001-00                           +000000015 10:20:30.000000000


關於numtodsinterval 參考文獻########################################

Oracle/PLSQL: NumToDSInterval Function


In Oracle/PLSQL, the numtodsinterval function converts a number to an INTERVAL DAY TO SECOND literal.

The syntax for the numtodsinterval function is:

numtodsinterval( number, expression )

number is the number to convert to an interval.

expression is the unit. It must be one of the following values: DAY, HOUR, MINUTE, or SECOND.


Applies To:

  • Oracle 8i, Oracle 9i, Oracle 10g, Oracle 11g

For example:

numtodsinterval(150, 'DAY')would return '+000000150'
numtodsinterval(1500, 'HOUR')would return '+000000062'
numtodsinterval(15000, 'MINUTE')would return '+000000010'
numtodsinterval(150000, 'SECOND')would return '+000000001'

###############################################
 注:to_char函式支援date和timestamp,但是trunc卻不支援TIMESTAMP資料型別 
 SQL> select trunc(to_date('20100908','yyyymmdd') - to_date('20100907','yyyymmdd')) m from dual; 
         M
----------
         1
--兩個相減的timestamp型別不能用trunc
SQL> select trunc(to_timestamp('20100908','yyyymmdd') - to_timestamp('20100907','yyyymmdd')) m from dual;
 
select trunc(to_timestamp('20100908','yyyymmdd') - to_timestamp('20100907','yyyymmdd')) m from dual
 
ORA-00932: 資料型別不一致: 應為 NUMBER, 但卻獲得 INTERVAL DAY TO SECOND


 to_char的使用:
 SQL> SELECT sysdate,systimestamp,to_char(systimestamp,'yyyymmdd hh24:mi:ssxff3') FROM dual;
 
SYSDATE     SYSTIMESTAMP                                             TO_CHAR(SYSTIMESTAMP,'YYYYMMDD'
----------- -------------------------------------------------------- ------------------------------
2010-12-2 1 02-12月-10 02.06.34.046000 下午 +08:00                       20101202 14:06:34.046

對於 timestamp型別的資料直接相減可以精確到秒以後
SQL> select systimestamp-systimestamp from dual;
SYSTIMESTAMP-SYSTIMESTAMP
---------------------------------------
+000000000 00:00:00.000000
        
四、interval year to month 型別的使用

interval year to month 可以用numtoyminterval或to_yminterval函式替代
SQL> select numtoyminterval(5,'year') + numtoyminterval(2,'month') from dual;
 
NUMTOYMINTERVAL(5,'YEAR')+NUMT
---------------------------------------
+000000005-02

SQL> select numtoyminterval(5*12+2,'month') from dual;
 
NUMTOYMINTERVAL(5*12+2,'MONTH'
---------------------------------------
+000000005-02

SQL> select to_yminterval('5-2') from dual;
 
TO_YMINTERVAL('5-2')
---------------------------------------
+000000005-02

SQL> select interval '5-2' year to month from dual;
 
INTERVAL'5-2'YEARTOMONTH
---------------------------------------
+05-02


五、interval day to second 型別的使用

interval day to second 可以用numtodsinterval或to_dsinterval替換使用
SQL> select numtodsinterval(10, 'day') + numtodsinterval(2, 'hour') +
  2         numtodsinterval(3, 'minute') + numtodsinterval(2.3312, 'second')

  3    from dual;
 
NUMTODSINTERVAL(10,'DAY')+NUMT
---------------------------------------
+000000010 02:03:02.331200000

SQL> select numtodsinterval(10*24*60*60+2*3600+3*60+2.3312, 'second') from dual;
 
NUMTODSINTERVAL(10*24*60*60+2*
---------------------------------------
+000000010 02:03:02.331200000

SQL> select to_dsinterval('10 02:03:02.3312') from dual;
 
TO_DSINTERVAL('1002:03:02.3312'
---------------------------------------
+000000010 02:03:02.331200000

SQL> select interval '10 02:03:02.3312' day to second from dual;
 
INTERVAL'1002:03:02.3312'DAYTO
---------------------------------------
+10 02:03:02.331200

六、時間函式

ADD_MONTHS 函式
ADD_MONTHS函式將一個日期上加上一指定的月份數,所以,日期中的日將是不變的。然而,如果開始日期是某月的最後一天,那麼,結果將會調整以使
返回值仍對應新的一月的最後一天。如果,結果月份的天數比開始月份的天數少,那麼,也會向回撥整以適應有效日期
select ADD_MONTHS(TO_DATE('15-11-1961','dd-mm-yyyy'),1) from dual; --1961-12-15
select ADD_MONTHS(TO_DATE('30-11-1961','dd-mm-yyyy'),1) from dual; --1961-12-31
select ADD_MONTHS(TO_DATE('31-1-1999','dd-mm-yyyy'),1) from dual;--1999-2-28

MONTHS_BETWEEN 函式
MONTHS_BETWEEN (x, y)用於計算x和y之間有幾個月。如果x在日曆中比y早,那麼MONTHS_BETWEEN()就返回一個負數。
                   當x 和 y 之間的月份之差不是整月的時候,可以採用小數表示

NUMTODSINTERVAL()函式
NUMTODSINTERVAL(x, interval_unit)用於將以interval_unit指定的值為單位的數字x轉換為一個INTERVAL DAY TO SECOND型別,
                                 interval_unit引數可以設定為DAY、 HOUR、MINUTE或SECOND。

NUMTOYMINTERVAL()函式
NUMTOYMINTERVAL(x, interval_unit)用於將以interval_unit指定的值為單位的數字x轉換為一個INTERVAL YEAR TO MONTH型別,
                                 interval_unit引數可以設定為YEAR或MONTH。




來自 “ ITPUB部落格 ” ,連結:http://blog.itpub.net/12272958/viewspace-706415/,如需轉載,請註明出處,否則將追究法律責任。

相關文章