java計算時間差及比較時間

yangxi_001發表於2014-10-22

比如: 現在是2004-03-26 13:31:40

           過去是:2004-01-02 11:30:24

我現在要獲得兩個日期差,差的形式為:XX天XX小時XX分XX秒

方法一:

DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try

{

    Date d1 = df.parse("2004-03-26 13:31:40");

    Date d2 = df.parse("2004-01-02 11:30:24");

    long diff = d1.getTime() - d2.getTime();

    long days = diff / (1000 * 60 * 60 * 24);

}

catch (Exception e)

{

}

方法二:

   SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

   java.util.Date now = df.parse("2004-03-26 13:31:40");

   java.util.Date date=df.parse("2004-01-02 11:30:24");

   long l=now.getTime()-date.getTime();

   long day=l/(24*60*60*1000);

   long hour=(l/(60*60*1000)-day*24);

   long min=((l/(60*1000))-day*24*60-hour*60);

   long s=(l/1000-day*24*60*60-hour*60*60-min*60);

   System.out.println(""+day+"天"+hour+"小時"+min+"分"+s+"秒");

方法三:

   SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

   java.util.Date begin=dfs.parse("2004-01-02 11:30:24");

   java.util.Date end = dfs.parse("2004-03-26 13:31:40");

   long between=(end.getTime()-begin.getTime())/1000;//除以1000是為了轉換成秒

   long day1=between/(24*3600);

   long hour1=between%(24*3600)/3600;

   long minute1=between%3600/60;

   long second1=between%60/60;

   System.out.println(""+day1+"天"+hour1+"小時"+minute1+"分"+second1+"秒");

====================================================

java 比較時間大小

String s1="2008-01-25 09:12:09";

String s2="2008-01-29 09:12:11";

java.text.DateFormat df=new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java.util.Calendar c1=java.util.Calendar.getInstance();

java.util.Calendar c2=java.util.Calendar.getInstance();

try

{

    c1.setTime(df.parse(s1));

    c2.setTime(df.parse(s2));

}catch(java.text.ParseException e){

    System.err.println("格式不正確");

}

int result=c1.compareTo(c2);

if(result==0)

    System.out.println("c1相等c2");

else if(result<0)

    System.out.println("c1小於c2");

else

    System.out.println("c1大於c2");

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