藍橋杯 演算法提高 P0102（Java解題）

程式碼：

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner s = new Scanner(System.in);
		String x = s.next();//輸入字串
		String t = Integer.valueOf(x, 16).toString();//將其轉化為16進位制
		/**將字串型別t轉化為整型ten*/
		char[] tt = new char[4];
		int[] ttt = new int[4];
		int ten = 0;
		for (int i = 0; i < t.length(); i++) {
			tt[i] = t.charAt(i);//先將字串轉化為字元
			ttt[i] = tt[i] - '0';//將字元轉化為整型
			ten = ten * 10 + ttt[i];
		}
		/**判斷字元位數，若不夠前面補0。*/
		if (x.length() == 1)
			System.out.println("Hex: 0x00" + x);
		else if (x.length() == 2)
			System.out.println("Hex: 0x0" + x);
		else if (x.length() == 3)
			System.out.println("Hex: 0x" + x);
		
		System.out.println("Decimal: "+t);//輸出十進位制數
		String e = Integer.toOctalString(ten);//將十進位制轉化為8進位制
		/**判斷字元位數，若不夠前面補0。*/
		if (e.length() == 1)
			System.out.println("Octal: 000" + e);
		else if (e.length() == 2)
			System.out.println("Octal: 00" + e);
		else if (e.length() == 3)
			System.out.println("Octal: 0" + e);
		if (e.length() == 4)
			System.out.println("Octal: " + e);
	}
}