數學-錯位相減法

云小兮發表於2024-09-08

1+\(\frac{1}{3}\)+\(\frac{1}{3^2}\)+\(\frac{1}{3^3}\)+\(\frac{1}{3^4}\)+\(\frac{1}{3^5}\)+\(\frac{1}{3^6}\)+\(\frac{1}{3^7}\)+······+\(\frac{1}{3^10}\)
\(\frac{1}{3}\)s=\(\frac{1}{3^10}\)-1
s=\(\frac{1}{3^11}\)-1

相關文章