密碼複雜度設定函式

skyin_1603發表於2016-11-11

@?/rdbms/admin/utlpwdmg.sql
這裡分享一個賬戶密碼複雜度設定函式,這個是作為資料庫使用者管理概要檔案的一部分

CREATE OR REPLACE FUNCTION verify_function_11G

(username varchar2,

  password varchar2,

  old_password varchar2)

  RETURN boolean IS

   n boolean;

   m integer;

   differ integer;

   isdigit boolean;

   ischar  boolean;

   ispunct boolean;

   db_name varchar2(40);

   digitarray varchar2(20);

   punctarray varchar2(25);

   chararray varchar2(52);

   i_char varchar2(10);

   simple_password varchar2(10);

   reverse_user varchar2(32);


BEGIN

   digitarray:= '0123456789';

   chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';


   -- Check for the minimum length of the password

   IF length(password) < 8 THEN

      raise_application_error(-20001, 'Password length less than 8');

   END IF;



   -- Check if the password is same as the username or username(1-100)

   IF NLS_LOWER(password) = NLS_LOWER(username) THEN

     raise_application_error(-20002, 'Password same as or similar to user');

   END IF;

   FOR i IN 1..100 LOOP

      i_char := to_char(i);

      if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN

        raise_application_error(-20005, 'Password same as or similar to user name ');

      END IF;

    END LOOP;


   -- Check if the password is same as the username reversed


   FOR i in REVERSE 1..length(username) LOOP

     reverse_user := reverse_user || substr(username, i, 1);

   END LOOP;

   IF NLS_LOWER(password) = NLS_LOWER(reverse_user) THEN

     raise_application_error(-20003, 'Password same as username reversed');

   END IF;


   -- Check if the password is the same as server name and or servername(1-100)

   select name into db_name from sys.v$database;

   if NLS_LOWER(db_name) = NLS_LOWER(password) THEN

      raise_application_error(-20004, 'Password same as or similar to server name');

   END IF;

   FOR i IN 1..100 LOOP

      i_char := to_char(i);

      if NLS_LOWER(db_name)|| i_char = NLS_LOWER(password) THEN

        raise_application_error(-20005, 'Password same as or similar to server name ');

      END IF;

    END LOOP;


   -- Check if the password is too simple. A dictionary of words may be

   -- maintained and a check may be made so as not to allow the words

   -- that are too simple for the password.

   IF NLS_LOWER(password) IN ('welcome1', 'database1', 'account1', 'user1234', 'password1', 'oracle123', 'computer1', 'abcdefg1', 'change_on_install') THEN

      raise_application_error(-20006, 'Password too simple');

   END IF;


   -- Check if the password is the same as oracle (1-100)

    simple_password := 'oracle';

    FOR i IN 1..100 LOOP

      i_char := to_char(i);

      if simple_password || i_char = NLS_LOWER(password) THEN

        raise_application_error(-20007, 'Password too simple ');

      END IF;

    END LOOP;


   -- Check if the password contains at least one letter, one digit

   -- 1. Check for the digit

   isdigit:=FALSE;

   m := length(password);

   FOR i IN 1..10 LOOP

      FOR j IN 1..m LOOP

         IF substr(password,j,1) = substr(digitarray,i,1) THEN

            isdigit:=TRUE;

             GOTO findchar;

         END IF;

      END LOOP;

   END LOOP;


   IF isdigit = FALSE THEN

      raise_application_error(-20008, 'Password must contain at least one digit, one character');

   END IF;

   -- 2. Check for the character

   <>

   ischar:=FALSE;

   FOR i IN 1..length(chararray) LOOP

      FOR j IN 1..m LOOP

         IF substr(password,j,1) = substr(chararray,i,1) THEN

            ischar:=TRUE;

             GOTO endsearch;

         END IF;

      END LOOP;

   END LOOP;

   IF ischar = FALSE THEN

      raise_application_error(-20009, 'Password must contain at least one \

              digit, and one character');

   END IF;



   <>

   -- Check if the password differs from the previous password by at least

   -- 3 letters

   IF old_password IS NOT NULL THEN

     differ := length(old_password) - length(password);


     differ := abs(differ);

     IF differ < 3 THEN

       IF length(password) < length(old_password) THEN

         m := length(password);

       ELSE

         m := length(old_password);

       END IF;


       FOR i IN 1..m LOOP

         IF substr(password,i,1) != substr(old_password,i,1) THEN

           differ := differ + 1;

         END IF;

       END LOOP;


       IF differ < 3 THEN

         raise_application_error(-20011, 'Password should differ from the \

            old password by at least 3 characters');

       END IF;

     END IF;

   END IF;

   -- Everything is fine; return TRUE ;

   RETURN(TRUE);

END;

來自 “ ITPUB部落格 ” ,連結:http://blog.itpub.net/31392094/viewspace-2128283/,如需轉載,請註明出處,否則將追究法律責任。

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