【轉】 js陣列 Array 交集 並集 差集 去重

原文：http://blog.csdn.net/ma_jiang/article/details/52672762

最勁專案需要用到js陣列去重和交集的一些運算，我的陣列元素個數可能到達1000以上，網上的實現方式都是2次迴圈，效能不適合我的需求，1000*1000那次數太多了，所以我這裡採用物件object來做處理，用空間換時間，code 如下：

///集合取交集  
Array.intersect = function () {  
    var result = new Array();  
    var obj = {};  
    for (var i = 0; i < arguments.length; i++) {  
        for (var j = 0; j < arguments[i].length; j++) {  
            var str = arguments[i][j];  
            if (!obj[str]) {  
                obj[str] = 1;  
            }  
            else {  
                obj[str]++;  
                if (obj[str] == arguments.length)  
                {  
                    result.push(str);  
                }  
            }//end else  
        }//end for j  
    }//end for i  
    return result;  
}  
  
//集合去掉重複  
Array.prototype.uniquelize = function () {  
    var tmp = {},  
        ret = [];  
    for (var i = 0, j = this.length; i < j; i++) {  
        if (!tmp[this[i]]) {  
            tmp[this[i]] = 1;  
            ret.push(this[i]);  
        }  
    }  
  
    return ret;  
}  
//並集  
Array.union = function () {  
    var arr = new Array();  
    var obj = {};  
    for (var i = 0; i < arguments.length; i++) {  
        for (var j = 0; j < arguments[i].length; j++)  
        {  
            var str=arguments[i][j];  
            if (!obj[str])  
            {  
                obj[str] = 1;  
                arr.push(str);  
            }  
        }//end for j  
    }//end for i  
    return arr;  
}  
  
//2個集合的差集 在arr不存在  
Array.prototype.minus = function (arr) {  
    var result = new Array();  
    var obj = {};  
    for (var i = 0; i < arr.length; i++) {  
        obj[arr[i]] = 1;  
    }  
    for (var j = 0; j < this.length; j++) {  
        if (!obj[this[j]])  
        {  
            obj[this[j]] = 1;  
            result.push(this[j]);  
        }  
    }  
    return result;  
};  
  
console.log(Array.intersect(["1", "2", "3"], ["2", "3", "4", "5", "6"]));//[2,3]  
console.log([1, 2, 3, 2, 3, 4, 5, 6].uniquelize());//[1,2,3,4,5,6]  
console.log(Array.union(["1", "2", "3"], ["2", "3", "4", "5", "6"], ["5", "6", "7", "8", "9"]))  
console.log(["2", "3", "4", "5", "6"].minus(["1", "2", "3"]));