Assume you have an array of length n initialized with all 0's and are given k update operations.
Each operation is represented as a triplet: [startIndex, endIndex, inc] which increments each element of subarray A[startIndex ... endIndex] (startIndex and endIndex inclusive) with inc.
Return the modified array after all k operations were executed.
Example:
Given: length = 5, updates = [ [1, 3, 2], [2, 4, 3], [0, 2, -2] ] Output: [-2, 0, 3, 5, 3]
Explanation:
Initial state: [ 0, 0, 0, 0, 0 ] After applying operation [1, 3, 2]: [ 0, 2, 2, 2, 0 ] After applying operation [2, 4, 3]: [ 0, 2, 5, 5, 3 ] After applying operation [0, 2, -2]: [-2, 0, 3, 5, 3 ]
Solution:
1 public class Solution { 2 public int[] getModifiedArray(int length, int[][] updates) { 3 int[] res = new int[length]; 4 Arrays.fill(res,0); 5 for (int[] update : updates){ 6 int start = update[0]; 7 int end = update[1]+1; 8 int val = update[2]; 9 10 res[start] += val; 11 if (end<length){ 12 res[end] -= val; 13 } 14 } 15 16 int sum = 0; 17 for (int i=0;i<length;i++){ 18 sum += res[i]; 19 res[i] = sum; 20 } 21 return res; 22 } 23 }