Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
Analysis:
Shift result to left by 1 bit, get the last bit of n, put the bit onto result.
Solution:
public class Solution { // you need treat n as an unsigned value public int reverseBits(int n) { if (n==0) return 0; int res = 0; for (int i=0;i<32;i++){ res = (res << 1); if ((n & 1)==1) res++; n = n >> 1; } return res; } }