排個序,求前k個元素和即可
int minimum(int K, vector <int> danceCost) { sort(danceCost.begin(),danceCost.end()); return accumulate(danceCost.begin(),danceCost.begin()+K,0); }
排個序,求前k個元素和即可
int minimum(int K, vector <int> danceCost) { sort(danceCost.begin(),danceCost.end()); return accumulate(danceCost.begin(),danceCost.begin()+K,0); }