判斷一個類是否為另一個類的例項 instanceof關鍵字和isAssignableFrom方法的區別

Zollty發表於2013-10-28

Which of the following is better?

a instanceof B

or

B.class.isAssignableFrom(a.getClass())

The only difference that I know of is, when 'a' is null, the first returns false, while the second throws an exception. Other than that, do they always give the same result?

When using instanceof, you need to know the class of "B" at compile time. When using isAssignableFrom()it can be dynamic and change during runtime.

 

2013年10月28日13分10秒

 

instanceof can only be used with reference types, not primitive types. isAssignableFrom() can be used with any class objects:

a instanceof int  // syntax error
3 instanceof Foo  // syntax error
int.class.isAssignableFrom(int.class)  // true

See http://java.sun.com/javase/6/docs/api/java/lang/Class.html#isAssignableFrom(java.lang.Class).

 

2013年10月28日13分10秒

 

Talking in terms of performance :

class A{}
class B extends A{}

A b = new B();

void execute(){
   boolean test = A.class.isAssignableFrom(b.getClass());
   // boolean test = A.class.isInstance(b);
   // boolean test = b instanceof A;
}

@Test
public void testPerf() {
    // Warmup the code
    for (int i = 0; i < 100; ++i)
        execute();

    // Time it
    int count = 100000;
    final long start = System.nanoTime();
    for(int i=0; i<count; i++){
       execute();
    }
    final long elapsed = System.nanoTime() - start;
    System.out.println(count+" iterations took " + TimeUnit.NANOSECONDS.toMillis(elapsed) + "ms.);
}

It gives :

  • A.class.isAssignableFrom(b.getClass()) : 100000 iterations took 15ms
  • A.class.isInstance(b) : 100000 iterations took 12ms
  • b instanceof A : 100000 iterations took 6ms

So that we can conclude instanceof is faster !

 

2013年10月28日13分10秒

 

A more direct equivalent to a instanceof B is

B.class.isInstance(a)

This works (returns false) when a is null too.

 

2013年10月27日13分10秒

 

Apart from basic differences mentioned above, there is a core subtle difference between instanceof operator and isAssignableFrom method in Class.

Read instanceof as “is this (the left part) the instance of this or any subclass of this (the right part)” and readx.getClass().isAssignableFrom(Y.class) as “Can I write X x = new Y()”. In other words, instanceof operator checks if the left object is same or subclass of right class, while isAssignableFrom checks if we can assign object of the parameter class (from) to the reference of the class on which the method is called. Note that both of these consider the actual instance not the reference type.

Consider an example of 3 classes A, B and C where C extends B and B extends A.

B b = new C();

System.out.println(b instanceof A); //is b (which is actually class C object) instance of A, yes. This will return true.  
System.out.println(b instanceof B); // is b (which is actually class C object) instance of B, yes. This will return true.  
System.out.println(b instanceof C); // is b (which is actually class C object) instance of C, yes. This will return true. If the first statement would be B b = new B(), this would have been false.
System.out.println(b.getClass().isAssignableFrom(A.class));//Can I write C c = new A(), no. So this is false.
System.out.println(b.getClass().isAssignableFrom(B.class)); //Can I write C c = new B(), no. So this is false.
System.out.println(b.getClass().isAssignableFrom(C.class)); //Can I write C c = new C(), Yes. So this is true.

 

2013年10月27日13分10秒

 

There is also another difference:

null instanceof X is false no matter what X is

null.getClass().isAssignableFrom(X) will throw a NullPointerException

 

2013年10月28日13分10秒

 

There is yet another difference. If the type (Class) to test against is dynamic, e.g. passed as a method parameter, then instanceof won't cut it for you.

boolean test(Class clazz) {
   return (this instanceof clazz); // clazz cannot be resolved to a type.
}

but you can do:

boolean test(Class clazz) {
   return (clazz.isAssignableFrom(this.getClass())); // okidoki
}

Oops, I see this answer is already covered. Maybe this example is helpful to someone.

 

2013年10月28日13分10秒

 

This thread provided me some insight into how instanceof differed from isAssignableFrom, so I thought I'd share something of my own.

I have found that using isAssignableFrom to be the only (probably not the only, but possibly the easiest) way to ask one's self if a reference of one class can take instances of another, when one has instances of neither class to do the comparison.

Hence, I didn't find using the instanceof operator to compare assignability to be a good idea when all I had were classes, unless I contemplated creating an instance from one of the classes; I thought this would be sloppy.

 

2013年10月28日13分10秒

 

Consider following situation. Suppose you want to check whether type A is a super class of the type of obj, you can go either

... A.class.isAssignableFrom(obj.getClass()) ...

OR

... obj instanceof A ...

But the isAssignableFrom solution requires that the type of obj be visible here. If this is not the case (e.g., the type of obj might be of a private inner class), this option is out. However, the instanceof solution would always work.

 

2013年10月27日13分10秒

 

some tests we did in our team show that A.class.isAssignableFrom(B.getClass()) works faster than B instanceof A. this can be very useful if you need to check this on large number of elements.

 

2013年10月28日13分10秒

 

instanceof cannot be used with primitive types or generic types either. As in the following code:

//Define Class< T > type ...

Object e = new Object();

if(e instanceof T) {
  // Do something.
}

The error is: Cannot perform instanceof check against type parameter T. Use it's erasure Obect instead since further generic type information will be erased at runtime.

Does not compile due to type erasure removing the runtime reference. However, the code below will compile:

if( type.isAssignableFrom(e.getClass())){
  // Do something.
}

 

2013年10月27日13分10秒

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