LaTeX 分母有理化運算

Thesmophoria發表於2020-12-04

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\frac{1}{\sqrt{a}}=\frac{\sqrt{a}}{\sqrt{a}\sqrt{a}}=\frac{\sqrt{a}}a

1 a = a a a = a a \frac{1}{\sqrt{a}}=\frac{\sqrt{a}}{\sqrt{a}\sqrt{a}}=\frac{\sqrt{a}}a a ​1​=a ​a ​a ​​=aa ​​

$\frac{1}{\sqrt{a}+\sqrt{b}}=\frac{\sqrt{a}-\sqrt{b}}{\left(\sqrt{a+b}\right)\left(\sqrt{a-b}\right)}=\frac{\sqrt{a}-\sqrt{b}}{a-b}$

1 a + b = a − b ( a + b ) ( a − b ) = a − b a − b \frac{1}{\sqrt{a}+\sqrt{b}}=\frac{\sqrt{a}-\sqrt{b}}{(\sqrt{a+b})(\sqrt{a-b})}=\frac{\sqrt{a}-\sqrt{b}}{a-b} a ​+b ​1​=(a+b ​)(a−b ​)a ​−b ​​=a−ba ​−b ​​

$\frac{1}{\sqrt{a}-\sqrt{b}}=\frac{\sqrt{a}+\sqrt{b}}{(\sqrt{a}-\sqrt{b}){(\sqrt{a}+\sqrt{b})}=\frac{\sqrt{a}+\sqrt{b}}{a-b}$

1 a − b = a + b ( a − b ) ( a + b ) = a + b a − b \frac{1}{\sqrt{a}-\sqrt{b}}=\frac{\sqrt{a}+\sqrt{b}}{(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})}=\frac{\sqrt{a}+\sqrt{b}}{a-b} a ​−b ​1​=(a ​−b ​)(a ​+b ​)a ​+b ​​=a−ba ​+b ​​

Exponent ^{}
^{}

Square
2 ^{2} 2

Ceil
⌈ ⌉ \left\lceil \right\rceil ⌈⌉

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