*LeetCode-Meeting Rooms II
首先interval陣列按照start 排序 然後建立一個以end排序的priority queue 這樣每次按照start的先後順序入隊,入隊之前要把所有在這個start之前都結束的會議poll出來
每次更新room數量
public class Solution {
public int minMeetingRooms(Interval[] intervals) {
Arrays.sort ( intervals, new Comparator<Interval>(){
public int compare ( Interval int1, Interval int2 ){
return int1.start - int2.start;
}
});
PriorityQueue <Interval> que = new PriorityQueue<Interval>( new Comparator<Interval>(){
public int compare ( Interval int1, Interval int2 ){
return int1.end - int2.end;
}
});
int rooms = 0;
for ( int i = 0; i < intervals.length; i ++ ){
while ( !que.isEmpty() && que.peek().end <= intervals[ i ].start ){
que.poll();
}
que.offer ( intervals[ i ] );
rooms = Math.max ( rooms, que.size() );
}
return rooms;
}
}
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