Oracle INTERVAL YEAR TO MONTH 和INTERVAL DAY TO SECOND 資料型別

逍遙三人發表於2012-03-15


Oracle INTERVAL YEAR TO MONTH資料型別
INTERVAL YEAR TO MONTH資料型別

Oracle語法:
INTERVAL 'integer [- integer]' {YEAR | MONTH} [(precision)][TO {YEAR | MONTH}]

該資料型別常用來表示一段時間差, 注意時間差只精確到年和月. precision為年或月的精確域, 有效範圍是0到9, 預設值為2.

eg:
INTERVAL '123-2' YEAR(3) TO MONTH     
表示: 123年2個月, "YEAR(3)" 表示年的精度為3, 可見"123"剛好為3為有效數值, 如果該處YEAR(n), n<3就會出錯, 注意預設是2.

INTERVAL '123' YEAR(3)
表示: 123年0個月

INTERVAL '300' MONTH(3)
表示: 300個月, 注意該處MONTH的精度是3啊.

INTERVAL '4' YEAR     
表示: 4年, 同 INTERVAL '4-0' YEAR TO MONTH 是一樣的

INTERVAL '50' MONTH     
表示: 50個月, 同 INTERVAL '4-2' YEAR TO MONTH 是一樣

INTERVAL '123' YEAR     
表示: 該處表示有錯誤, 123精度是3了, 但系統預設是2, 所以該處應該寫成 INTERVAL '123' YEAR(3) 或"3"改成大於3小於等於9的數值都可以的

INTERVAL '5-3' YEAR TO MONTH + INTERVAL '20' MONTH =
INTERVAL '6-11' YEAR TO MONTH
表示: 5年3個月 + 20個月 = 6年11個月

與該型別相關的函式:
NUMTODSINTERVAL(n, 'interval_unit')
將n轉換成interval_unit所指定的值, interval_unit可以為: DAY, HOUR, MINUTE, SECOND
注意該函式不可以轉換成YEAR和MONTH的.

NUMTOYMINTERVAL(n, 'interval_unit')
interval_unit可以為: YEAR, MONTH

eg: (Oracle Version 9204, RedHat Linux 9.0)
SQL> select numtodsinterval(100,'DAY') from dual;

NUMTODSINTERVAL(100,'DAY')                                                      
---------------------------------------------------------------------------     
+000000100 00:00:00.000000000                                                   

SQL> c/DAY/SECOND
  1* select numtodsinterval(100,'SECOND') from dual
SQL> /

NUMTODSINTERVAL(100,'SECOND')                                                   
---------------------------------------------------------------------------     
+000000000 00:01:40.000000000                                                   

SQL> c/SECOND/MINUTE
  1* select numtodsinterval(100,'MINUTE') from dual
SQL> /

NUMTODSINTERVAL(100,'MINUTE')                                                   
---------------------------------------------------------------------------     
+000000000 01:40:00.000000000                                                   

SQL> c/MINUTE/HOUR
  1* select numtodsinterval(100,'HOUR') from dual
SQL> /

NUMTODSINTERVAL(100,'HOUR')                                                     
---------------------------------------------------------------------------     
+000000004 04:00:00.000000000                                                   

SQL> c/HOUR/YEAR
  1* select numtodsinterval(100,'YEAR') from dual
SQL> /
select numtodsinterval(100,'YEAR') from dual
                           *
ERROR at line 1:
ORA-01760: illegal argument for function

SQL> select numtoyminterval(100,'year') from dual;

NUMTOYMINTERVAL(100,'YEAR')                                                     
---------------------------------------------------------------------------     
+000000100-00                                                                   

SQL> c/year/month
  1* select numtoyminterval(100,'month') from dual
SQL> /

NUMTOYMINTERVAL(100,'MONTH')                                                    
---------------------------------------------------------------------------     
+000000008-04                                                                   


時間的計算:
SQL> select to_date('1999-12-12','yyyy-mm-dd') - to_date('1999-12-01','yyyy-mm-dd') from dual;

TO_DATE('1999-12-12','YYYY-MM-DD')-TO_DATE('1999-12-01','YYYY-MM-DD')           
---------------------------------------------------------------------           
                                                                   11           
-- 可以相減的結果為天.

SQL> c/1999-12-12/1999-01-12
  1* select to_date('1999-01-12','yyyy-mm-dd') - to_date('1999-12-01','yyyy-mm-dd') from dual
SQL> /

TO_DATE('1999-01-12','YYYY-MM-DD')-TO_DATE('1999-12-01','YYYY-MM-DD')           
---------------------------------------------------------------------           
                                                                 -323           
-- 也可以為負數的

SQL> c/1999-01-12/2999-10-12
  1* select to_date('2999-10-12','yyyy-mm-dd') - to_date('1999-12-01','yyyy-mm-dd') from dual
SQL> /

TO_DATE('2999-10-12','YYYY-MM-DD')-TO_DATE('1999-12-01','YYYY-MM-DD')           
---------------------------------------------------------------------           
                                                               365193           

下面看看INTERVAL YEAR TO MONTH怎麼用.
SQL> create table bb(a date, b date, c interval year(9) to month);

Table created.

SQL> desc bb;
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 A                                                  DATE
 B                                                  DATE
 C                                                  INTERVAL YEAR(9) TO MONTH

SQL> insert into bb values(to_date('1985-12-12', 'yyyy-mm-dd'), to_date('1984-12-01','yyyy-mm-dd'), null)

1 row created.

SQL> select * from bb;

A         B                                                                     
--------- ---------                                                             
C                                                                               
---------------------------------------------------------------------------     
12-DEC-85 01-DEC-84                                                             
                                                                                
                                                                               
SQL> update bb set c = numtoyminterval(a-b, 'year');

1 row updated.

SQL> select * from bb;

A         B                                                                    
--------- ---------                                                            
C                                                                              
---------------------------------------------------------------------------    
12-DEC-85 01-DEC-84                                                            
+000000376-00                                                                  
                                                                               
-- 直接將相減的天變成年了, 因為我指定變成年的
SQL> select a-b, c from bb;

       A-B                                                                     
----------                                                                     
C                                                                              
---------------------------------------------------------------------------    
       376                                                                     
+000000376-00                                                                  
                                                                               

SQL> insert into bb values(null,null,numtoyminterval(376,'month'));

1 row created.

SQL> select * from bb;

A         B             C                                                       
--------- ---------    --------------------------------------------    
12-DEC-85 01-DEC-84    +000000376-00                                                                  
                         +000000031-04                                         

SQL> insert into bb values ( null,null, numtoyminterval(999999999,'year'));

1 row created.

SQL> select * from bb;

A           B            C                                
---------   ---------     ---------------------------------------------------------------------    
12-DEC-85   01-DEC-84   +000000376-00                                                                  
                          +000000031-04
                          +999999999-00                                                                
 

Oracle INTERVAL DAY TO SECOND資料型別
INTERVAL DAY TO SECOND資料型別

Oracle語法:
INTERVAL '{ integer | integer time_expr | time_expr }'
{ { DAY | HOUR | MINUTE } [ ( leading_precision ) ]
| SECOND [ ( leading_precision [, fractional_seconds_precision ] ) ] }
[ TO { DAY | HOUR | MINUTE | SECOND [ (fractional_seconds_precision) ] } ]

leading_precision值的範圍是0到9, 預設是2. time_expr的格式為:HH[:MI[:SS[.n]]] or MI[:SS[.n]] or SS[.n], n表示微秒.
該型別與INTERVAL YEAR TO MONTH有很多相似的地方,建議先看INTERVAL YEAR TO MONTH再看該文.

範圍值:
HOUR:    0 to 23
MINUTE: 0 to 59
SECOND: 0 to 59.999999999

eg:
INTERVAL '4 5:12:10.222' DAY TO SECOND(3)
表示: 4天5小時12分10.222秒

INTERVAL '4 5:12' DAY TO MINUTE
表示: 4天5小時12分

INTERVAL '400 5' DAY(3) TO HOUR
表示: 400天5小時, 400為3為精度,所以"DAY(3)", 注意預設值為2.

INTERVAL '400' DAY(3)
表示: 400天

INTERVAL '11:12:10.2222222' HOUR TO SECOND(7)
表示: 11小時12分10.2222222秒

INTERVAL '11:20' HOUR TO MINUTE
表示: 11小時20分

INTERVAL '10' HOUR
表示: 10小時

INTERVAL '10:22' MINUTE TO SECOND
表示: 10分22秒

INTERVAL '10' MINUTE
表示: 10分

INTERVAL '4' DAY
表示: 4天

INTERVAL '25' HOUR
表示: 25小時

INTERVAL '40' MINUTE
表示: 40分

INTERVAL '120' HOUR(3)
表示: 120小時

INTERVAL '30.12345' SECOND(2,4)     
表示: 30.1235秒, 因為該地方秒的後面精度設定為4, 要進行四捨五入.

INTERVAL '20' DAY - INTERVAL '240' HOUR = INTERVAL '10-0' DAY TO SECOND
表示: 20天 - 240小時 = 10天0秒


來自 “ ITPUB部落格 ” ,連結:http://blog.itpub.net/21584437/viewspace-718590/,如需轉載,請註明出處,否則將追究法律責任。

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