C#保留小數位數的方法

iDotNetSpace發表於2009-11-06
1.System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.NumberDecimalDigits =intDecLength; //要設定的小數位數
double strCashAmt=Convert.ToDouble(this.txtCashAmt.Text); //先把控制元件內的值轉成double
this.txtCashAmt.Text = strCashAmt.ToString("N",provider); //再利用ToString函式格式化小數位數

  2.保留N位,四捨五入 .

  decimal d= decimal.Round(decimal.Parse("0.55555"),2);

  3.保留N位四捨五入

  Math.Round(0.55555,2)

  4,保留N位四捨五入

  double dbdata = 0.55555;

  string str1 = dbdata.ToString("f2");//fN 保留N位,四捨五入

  5.保留N位四捨五入

string result = String.Format("{0:N2}", 0.55555);//2位
string result = String.Format("{0:N3}", 0.55555);//3位

  6. 保留N位四捨五入 (不錯)

  double s=0.55555;

  result=s.ToString("#0.00");//點後面幾個0就保留幾位

  C#下如果顯示保留小數位數,及百分號的解決方法:

  1、用NumberFormatInfo類來解決:

System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.PercentDecimalDigits = 2;//小數點保留幾位數.
provider.PercentPositivePattern = 2;//百分號出現在何處.
double result = (double)1 / 3;//一定要用double型別.
Response.Write(result.ToString("P", provider));
2、用toString方法.:
public string getRate(double hcount, double task)
{
string rValue;
string temp = "";
if (task == 0)
{
task = 1;
}
double db = (hcount / task) * 100;
if (hcount >= task)
{
rValue = "100%";
}
else
{
rValue = db.ToString("#0.#0") + "%";
}
return rValue;
}
string str1 = String.Format("{0:N1}",56789); //result: 56,789.0
string str2 = String.Format("{0:N2}",56789); //result: 56,789.00
string str3 = String.Format("{0:N3}",56789); //result: 56,789.000
string str8 = String.Format("{0:F1}",56789); //result: 56789.0
string str9 = String.Format("{0:F2}",56789); //result: 56789.00
string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89
string str12 =(56789 / 100).ToString("#.##"); //result: 567

來自 “ ITPUB部落格 ” ,連結:http://blog.itpub.net/12639172/viewspace-618278/,如需轉載,請註明出處,否則將追究法律責任。

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