Oracle Certificate Profession 1Z0-051-25

LuiseDalian發表於2014-05-10
Oracle
（25）You need to create a table with the following column specifications:

1. Employee ID (numeric data type) for each employee

2. Employee Name (character data type) that stores the employee name

3. Hire date, which stores the date of joining the organization for each employee

4. Status (character data type), that contains the value 'ACTIVE' if no data is entered

5. Resume (character large object [CLOB] data type), which contains the resume submitted by the employee

Which is the correct syntax to create this table?

A.

CREATE TABLE EMP_1

(

  emp_id        NUMBER(4),

  emp_name   VARCHAR2(25),

  start_date   DATE,

  e_status     VARCHAR2(10) DEFAULT 'ACTIVE',

  resume       CLOB(200)

);

B.

CREATE TABLE 1_EMP

(

  emp_id        NUMBER(4),

  emp_name   VARCHAR2(25),

  start_date    DATE,

  emp_status VARCHAR2(10) DEFAULT 'ACTIVE',

  resume       CLOB

);

C.

CREATE TABLE EMP_1

(

  emp_id        NUMBER(4),

  emp_name   VARCHAR2(25),

  start_date    DATE,

  emp_status VARCHAR2(10) DEFAULT "ACTIVE",

  resume       CLOB

);

D.

CREATE TABLE EMP_1

(

  emp_id         NUMBER,

  emp_name    VARCHAR2(25),

  start_date     DATE,

  emp_status  VARCHAR2(10) DEFAULT 'ACTIVE',

  resume        CLOB

);


答案：（D）

解析：

A（X），CLOB不能指定精度

B（X），表名得以字母開頭

C（X），emp_status列預設值應該為’ACTIVE’，不應該用雙引號



來自 “ ITPUB部落格 ” ，連結：http://blog.itpub.net/17013648/viewspace-1157925/，如需轉載，請註明出處，否則將追究法律責任。

相關文章