python開發中時長到貨幣格式化的問題,一般情況下可以使用locale模組。但是這個模組使用起來不是那麼順手,今天我為大家介紹一個很好用的方法。
直接上程式碼。。。
from decimal import * def moneyfmt(value, places=2, curr='', sep=',', dp='.',pos='', neg='-', trailneg=''): """Convert Decimal to a money formatted string. places: required number of places after the decimal point curr: optional currency symbol before the sign (may be blank) sep: optional grouping separator (comma, period, space, or blank) dp: decimal point indicator (comma or period) only specify as blank when places is zero pos: optional sign for positive numbers: '+', space or blank neg: optional sign for negative numbers: '-', '(', space or blank trailneg:optional trailing minus indicator: '-', ')', space or blank >>> d = Decimal('-1234567.8901') >>> moneyfmt(d, curr='$') '-$1,234,567.89' >>> moneyfmt(d, places=0, sep='.', dp='', neg='', trailneg='-') '1.234.568-' >>> moneyfmt(d, curr='$', neg='(', trailneg=')') '($1,234,567.89)' >>> moneyfmt(Decimal(123456789), sep=' ') '123 456 789.00' >>> moneyfmt(Decimal('-0.02'), neg='<', trailneg='>') '<0.02>' """ value = Decimal(value) q = Decimal(10) ** -places # 2 places --> '0.01' sign, digits, exp = value.quantize(q).as_tuple() result = [] digits = map(str, digits) build, next = result.append, digits.pop if sign: build(trailneg) for i in range(places): build(next() if digits else '0') build(dp) if not digits: build('0') i = 0 while digits: build(next()) i += 1 if i == 3 and digits: i = 0 build(sep) build(curr) build(neg if sign else pos) return ''.join(reversed(result)) print moneyfmt('1234.45',sep=',', dp='.')
結果:
1,234.45
很簡單吧。。。