最大公約數與最小公倍數演算法

#include <iostream>
#include <cstdio>

#define MAX(a,b) (a > b ? a : b)

template <class T>
T gcd(T a, T b)
{
    return a > b ? (b == 0 ? b : a%b) : gcd(b,a%b);
}

int main(void)
{
    int a,b;
    int resLcm = 0;
    int resGcd = 0;
    while (scanf("%d%d",&a,&b) != EOF)
    {
        resGcd = gcd(a,b);  //greatest common divisor
        resLcm = resGcd*MAX(a,b); //lowest common multiple
        printf("resGcd = %d\nresLcm= %d\n",resGcd,resLcm);
    }

    return 0;
}

上面的程式碼利用了下C++裡面的函式模版，更加通用。