js跳轉頁面方法(轉)

weixin_33912246發表於2017-05-22

<span id="tiao">3</span><a href="javascript:countDown"></a>布丁足跡;秒後自動跳轉……<meta http-equiv=refresh content=3;url='/search/billsearch.jsp'</ul>

<!--指令碼開始-->
<script language="javascript" type="">
function countDown(secs){
  tiao.innerText=secs;
  if(--secs>0)
   setTimeout("countDown("+secs+")",1000);
  }
  countDown(3);
</script>
<!--指令碼結束-->
 

  按鈕式:

  <INPUT name="pclog" type="button" value="GO" onClick="location.href='http://www.ddhbb.com/'">

  連結式:

  <a href="javascript:history.go(-1)">返回上一步</a>

  <a href="<%=Request.ServerVariables("HTTP_REFERER")%>">返回上一步</a>

  直接跳轉式:

  <script>window.location.href='http://www.ddhbb.com';</script>

  開新視窗:

  <a href="javascript:" onClick="window.open('http://www.ddhbb.com/blog/guestbook.asp','','height=500,width=611,scrollbars=yes,status=yes')">布丁          足跡</a>

 JS跳轉頁面參考程式碼
第一種:
<script language="javascript" type="text/javascript">
window.location.href="login.jsp?backurl="+window.location.href;
</script>
第二種:
<script language="javascript">
alert("返回");
window.history.back(-1);
</script>
第三種:
<script language="javascript">
window.navigate("top.jsp");
</script>
第四種:
<script language="JavaScript">
self.location=’top.htm’;
</script>
第五種:
<script language="javascript">
alert("非法訪問!");
top.location=’xx.jsp’;
</script>

=====javascript中彈出選擇框跳轉到其他頁面=====
<script language="javascript">
<!--
function logout()...{
if (confirm("你確定要登出身份嗎?是-選擇確定,否-選擇取消"))...{
window.location.href="logout.asp?act=logout"
}
}
-->
</script>
 

====javascript中彈出提示框跳轉到其他頁面=====
<script language="javascript">
<!--
function logout()...{
alert("你確定要登出身份嗎?");
window.location.href="logout.asp?act=logout"
}
-->
</script>

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