一段對16進位制字串進行異或的程式碼

FrankYou發表於2017-12-04

一段對16進位制字串進行異或的程式碼。

    public String xorHex(String a, String b) {
        char[] chars = new char[a.length()];
        for (int i = 0; i < chars.length; i++) {
            chars[i] = toHex(fromHex(a.charAt(i)) ^ fromHex(b.charAt(i)));
        }
        return new String(chars);
    }

    private static int fromHex(char c) {
        if (c >= '0' && c <= '9') {
            return c - '0';
        }
        if (c >= 'A' && c <= 'F') {
            return c - 'A' + 10;
        }
        if (c >= 'a' && c <= 'f') {
            return c - 'a' + 10;
        }
        throw new IllegalArgumentException();
    }

    private char toHex(int nybble) {
        if (nybble < 0 || nybble > 15) {
            throw new IllegalArgumentException();
        }
        return "0123456789ABCDEF".charAt(nybble);
    }

 

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